Translate verbal expression to an algebraic expression<br><br> 8 times a number x is subtracted by 4

I need some help... HOW DO I DO THISSSS. NOT ASKING YOU TO DO IT JUST HELP ME

torisob [31]

so obviously first of all find three sherical objects or balls of varioius sizes to make it easier get a large medium and small sized.

then on scratch paper sketch those objects (im assuming by the looks of it you would trace them if not just draw them then take measuring tape or a ruler across to measure said object) now you arent told what units to measure in but id assume to stick with one unit either inches or cm

mesure the length across which is the circumference

now you would just have to do your calculations by finding the radius and volume and surface area

remember volume is (*units) cubed and suface area is (*units) sqared

6 0

3 years ago

in 1991, a gallup poll reported this percent to be 79%. using the data from this poll, test the claim that the percent of driver

snow_lady [41]

We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.

Given,

The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.

In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.

To report the large-sample z statistic and its p-value,

Null hypothesis,

H₀ : p = 0.79

Alternative hypothesis,

Ha : p < 0.79

Level of significance, α = 0.01

Under H₀

Test statistic,

$Z_0= \frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n} } }$

Z₀ = -7.948

The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by

P-value = P(z <-7.945)

= 0.000 (from z-table)

Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.

To learn more about hypothesis click here:

brainly.com/question/17173491

#SPJ4

5 0

1 year ago

HELP!!! STATS!!!

Vadim26 [7]

Answer:

The 99% confidence interval is $165.776 < \mu < 180.224$

Step-by-step explanation:

From the question we are told that

The sample size is n = 100

The sample mean is $\= x = 173 \ days$

The population standard deviation is $\sigma = 28 \ days$

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

$E = 2.58 * \frac{28 }{\sqrt{100} }$

=> $E = 7.224$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $173 -7.224 < \mu < 173 + 7.224$

=> $165.776 < \mu < 180.224$

4 0

3 years ago

Help!! I hate geometryyyy

miskamm [114]

Answer:

AFB, BDC, and FBD

Step-by-step explanation:

3 0

4 years ago

Many people use scanners to read documents and store them into pdf file. To help determine which brand of scanner to buy, a stud

konstantin123 [22]

The data is missing in the question. The data is provided below :

Document : 1 2 3 4 5 6 7 8

Brand A 17 29 18 14 21 25 22 29

Brand B 21 38 15 19 22 30 31 37

Solution :

State of the hypothesis of the null hypothesis and alternate hypothesis.

Null hypothesis : $h_A = h_B$

Alternate hypothesis : $h_A > h_B$

These hypothesis is a one tailed test. The null hypothesis will get rejected when the mean difference between the sample means is very small.

Significance level = 0.05

Therefore the standard error is : $SE = \sqrt{(\frac{s^2_1}{n_1})+(\frac{s^2_2}{n_2})}$

= 3.602

And the degree of freedom, DF = 14

$t=\frac{(x_1-x_2)-d}{SE}$

= -1.319

Here, $s_1$ = standard deviation of the sample 1

$s_2$ = standard deviation of the sample 2

$n_1$ = size of the sample 1

$n_2$ = size of the sample 2

$x_1$ = mean of the sample 1

$x_2$ = mean of the sample 2

d = the hypothesis difference between the population mean

The observed difference in a sample means t static of -1.32. From t distribution calculator to determine P( $t \leq -1.32$ ) = 0.1042

Since the P value of 0.1042 is greater than significance level o 0.05, we therefore cannot reject the null hypothesis.

But from the test, we have no sufficient evidence that supports that Brand A is better than Brand B.

8 0

3 years ago

Translate verbal expression to an algebraic expression 8 times a number x is subtracted by 4