Answer:
Alternate-exterior angles theorem.
Step-by-step explanation:
Two parallel lines are cut by a transversal, and if there are a pair of congruent angles that are outside of the parallel lines, and on opposite sides of the transversal, you will have the alternate-exterior angles theorem.
You answered correctly.
(a brainliest would be appreciated)
The answer is :
.0085470085
Hope This Helps!!
:)
You can use the Law of Sines for this problem, but what makes it tough at first glance is that they put a step in before you can use it directly. That first step is to get m∠C. When solving a triangle, always get the third angle if you know the other two so that you can use the Law of Sines (or Law of Cosines) more directly.
The sum of the angles of any triangles is 180°. We know the measures of the two other angles. So we subtract them from 180° to find that third angle.
180° - 76° - 66° = 38°
Now we can use the proportion from the picture. Angle B measures 76°, side b is our unknown, Angle C measures 38°, and side c measures 3 units.
sin 76° sin 38°
----------- = -----------
b 3
Cross multiply to find b (the side). We carry out five places in these calculations to get more accuracy.
3 * sin 76° = b * sin 38°
b = 3 * sin 76° 3 * 0.56611 1.69832
--------------- = --------------- = ---------------- = 5.73044
sin 38° 0.29636 0.29636
To the nearest tenth, b - 5.7 units.
Answer:
15 ounces of red beans
Step-by-step explanation:
So, we know Kim's soup contains a total of 75 ounces of beans, including red beans (r) and black beans (b), so r + b = 75
Then we know that for each ounce of red beans, there are 4 ounces of black beans, 1b = 4r
Then we merge both equations by replacing b's value in the first equation by its equivalent (b = 4r), since we are looking for the count of red beans.
r + b = 75
r + 4r = 75
5 r = 75
r = 15
There are 15 ounces of red beans in Kim's soup, that looks a lot like the last chili I made :-)
