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kherson [118]
3 years ago
13

given: a= the square root of 3 b= 2 times the square root of 3 c= the square root of 25 d= the square root of 16 wich expression

results in a rational number?
Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0
I think it might be b
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Half the marbles in a bag are red, 1/6 of the marbles are blue, and the remaining 8 marbles are white how many total marbles are
Gemiola [76]

Hey there! I'm happy to help!

Let's represent the total number of marbles with the variable t. We have the following information.

1/2t+1/6t+8=t (1/2 of total are red, 1/6 of total are blue, 8 are white, add them up to get total)

Now, we solve for t.

1/2t+1/6t+8=t

We combine like terms.

2/3t+8=t

We subtract t from both sides.

-1/3t+8=0

We subtract 8 from both sides.

-1/3t=-8

We divide both sides by -1/3.

t=24

Therefore, there ae 24 total marbles in the bag.

Have a wonderful day! :D

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3 years ago
If it takes 4 gallons of gas to drive 92 miles how many miles can be driven using 6 gallons
AVprozaik [17]

Answer:

138

Step-by-step explanation:

as 92÷4 = 23 and 23x6 = 148

4 0
3 years ago
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Which value is closest to the unit length of MN in the coordinate plane below?
sergey [27]

Answer:

D

Step-by-step explanation:

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3 years ago
An object is thrown upward from the top of a 48-foot building with an initial velocity of 32 feetquadratic equation h = - 16t^2+
Alex17521 [72]

SOLUTION

The object would hit the ground at the root of the equation, that is where h = 0

So we have

\begin{gathered} h=-16t^2+32t+48=0 \\ -16t^2+32t+48=0 \\ 16t^2-32t-48=0 \\ divide\text{ through by 16} \\ t^2-2t-3=0 \end{gathered}

Solving the quadratic equation, we have

\begin{gathered} t^2-3t+t-3=0 \\ t(t-3)+1(t-3)=0 \\ (t-3)(t+1)=0 \\ t=3,\text{ or} \\ t=-1 \end{gathered}

So we ignore -1 as time cannot be negative.

Hence the object hit the ground in 3 seconds

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1 year ago
Which rule describes the composition of transformations that maps pre-image ABCD to final image A"B"C"D"?
almond37 [142]

The correct option will be:  r_{x-axis} \circ T_{-6,1} (x,y)

<em><u>Explanation</u></em>

We can see in the diagram that distances of A' , B', C' and D' from the x-axis are equal with the distances of A, B, C and D from the x-axis respectively.

That means, ABCD is first <u>reflected about the x-axis</u> to form A'B'C'D'

Now, A'', B'', C'' and D'' are located at <u>6 units left and 1 unit up</u> from A', B', C' and D'.

Thus, for getting the final image A''B''C''D'', we are first reflecting ABCD about the x-axis and then translated it 6 units left and 1 unit upward.  

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