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iris [78.8K]
3 years ago
8

Please answer the following questions.

Mathematics
1 answer:
Hatshy [7]3 years ago
7 0
  1. ∠2 & ∠7
  2. 8,15,17
  3. 720 °
  4. 36 feet
  5. 76 °
  6. Nonagon
  7. 59 °

Step-by-step explanation:

1. Alternate angles- Two angles are said to be alternate if they are not on the same side of the line, that intersects two other parallel lines. In the figure given above

∠1=∠8 & ∠5=∠4 (Exterior alternate angle)

∠6=∠3 & ∠2=∠7 (Interior alternate angle)

2. According to Pythagoras theorem, an essential condition for any triangle to be a right-angled triangle is (base)²+(perpendicular)²=(hypotenuse) ²

We selectively apply the given options to check which options fit in the given hypothesis.

Only (17)² = (15)² + (8) ²

3. The sum of all the interior angles of Hexagon is 6(number of sides) * 120° (measure of one interior angle)= 720°

4. In the question Height of the silo is 30 foot while the length of the shadow is 20 foot.  

Distance between the tip of the shadow to the top of the silo would be (silo height)² +(shadow)²=(distance) ²

Distance=√1300

∴Distance= 36 feet(approx.)

5. The measure of the central angle is equal to the arc it creates. Hence arc measure would be 76 °

6. Sum of the all the angles of the nonagon is 1260° while no of sides is 9

Each interior angle measures 140 °

7. In the given Figure ∠6 and ∠7 are conjugate pairs summing up to 180° (since x and y are parallel lines)

Hence ∠6 would measure 180-121=59 °

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Sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/sWhen Sharon jumps, Megan throws a beach
likoan [24]

Answer:

1.08 seconds

Step-by-step explanation:

given data

<u>first equation:</u>

According to the data, sharon position will be

h(t)= -16 t^{2} + 4t +18---->eq(1)  

<u>Second equation;</u>

When Sharon jumps, Megan throws a beach ball up to Sharon with an initial upward velocity of 16 ft/s from a height 5 feet off the ground to the nearest hundredth of a second

therefore, ball position would be

h(t)= -16t^{2} +16t +5 --->eq(2)

In order to find how long after she jumps does the ball reach Sharon i.e time, we will equate eq(1) and eq(2)

Therefore,

eq(1)= eq(2)

-16t^{2} +4t +18 = -16t^{2} + 16t +5  --->(further simplifying it)

-16t^{2} + 16t^{2} + 18 -5 = 16t - 4t

13 = 12t

t= 13/12

t= 1.08 s

Thus it took 1.08 seconds.

7 0
3 years ago
Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph.
Lelechka [254]

Answer:

Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)

Parallel: slopes both = -1/3

1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.

I will show the work for both the problems down below.

Step-by-step explanation:

Finding coordinates:

1+(-5)/2=-2  5+1/2=3

(-2,3)

1+4/2= 2.5   5+(-2)/2= 1.5

(2.5,1.5)

Show work verifying the EG and BC are parallel:

You can do this by finding the slope

Slop formula (y2-y1)/(x2-x1)

(1.5-3)/(2.5-(-2))

Then simplify

-1.5/2/5= -1/3 which i your slope. You use the same formula and follow thee same steps for the points of BC and both will come up as -1/4 meaning they are parallel.

Show work verifying that EG and BC are parallel:

Use distance formula to find how long each line is

√(x2-x1)^2+(y2-y1)^2

√(2.5-(-2)^2)+(1.5-3)^2

Simplify

√4.5+(1.5)=3

Do the same thing with BC and you will get 6






7 0
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Answer:

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Step-by-step explanation: hope this helps

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