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grin007 [14]
3 years ago
5

What is the square root of 8k=k

Mathematics
1 answer:
Leviafan [203]3 years ago
3 0
3.90506372e-23 m^2 kg s^-2 K^-1
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Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

\implies -6a+c=-9

But c=0

\implies -6a=-9

\implies a=\frac{3}{2}

C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
30 POINTS PLEASE help
aksik [14]

Answer:

m= -1/7

b=2

Step-by-step explanation:

5 0
3 years ago
A parabola has two x intercepts at (-2 , 0) and (3 , 0) and passes through the point (5 , 10). Find the equation of this parabol
Kamila [148]
Y = a(x + 2)(x - 3) : equation of the parabola in factored form 10 = a(5 + 2)(5 - 2) : (5 , 10) is a point on the graph of the parabola and therefore satisfies the equation of the parabola. a = 5/7: solve the above equation for a.
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3 years ago
Can someone please help me I don't get this at all
goldfiish [28.3K]

Answer:

A and D          B and A               C and B                 D and C

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Do you multiply area or add it
pogonyaev
It's the formula. Base times height.
For example: if 50 is the base and 10 is the height, just multiply them both.
50 x 10 = 500. And I don't think you add area-that's for finding the perimeter
5 0
3 years ago
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