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3 years ago

Drag each sequence to the correct location on the table.

Mathematics

1 answer:

ella [17]3 years ago

6 0

Answer:

Arithmetic: 3, 8, 13, 18,... , 4, 8, 12, 16,...

Geometric: 4, 8, 12, 16,... , 2,6, 18, 54,...

Neither: 5, 10, 20, 30,...

Step-by-step explanation:

An arithmetic sequence is a sequence that grows by addition, a geometric sequence is one that grows by multiplication.

3, 8, 13, 18,... is arithmetic because you add 5 each time to find the next term of the sequence.

5, 10, 20, 40,... is geometric because you multiply the previous term by a factor of 2 each time to find the next nerm of the sequence.

2,6, 18, 54,... is geometric because you multiply the previous term by a factor of 3 each time to find the next nerm of the sequence.

5, 10, 20, 30,... is neither because it does not follow the pattern set by the rules of geometric or arithmetic sequences.

4, 8, 12, 16,... is arithmetic because you add 4 each time to find the next term of the sequence.

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Answer: $3\ kilograms$

Step-by-step explanation:

It is important to remember that, by definition, proportional relationships have the following form:

$y=kx$

Where "k" is the constant of proportionality.

We know that Maddy assume that the relation between the volume and the weight is proportional.

Then, let be "V" the volume in liters and "w" the weight in kilograms.

We can write the following equation:

$V=kw$

So, if the boat of 555 liters weights 7.5 kilograms, we can find "k":

$555 =k(7)\\\\k=\frac{555}{7}\\\\k=74$

In order to solve the exercise, substitute the value of "k" and $V=222$ into the equation and solve for "w". Then:

$222=(74)w\\\\\frac{222}{74}=w\\\\w=3$

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3 years ago

The probability is 1 in 4,011,000 that a single auto trip in the United States will result in a fatality. Over a lifetime, an av

IrinaVladis [17]

Answer:

0.0114

Step-by-step explanation:

(a) What is the probability of a fatal accident over a lifetime?

Suppose A be the event of a fatal accident occurring in a single trip.

Given that:

P(1 single auto trip in the United States result in a fatality) = P(A)

Then;

P(A) = 1/4011000

P(A) = 2.493 × 10⁻⁷

Now;

P(1 single auto trip in the United States NOT resulting in a fatality) is:

P( $\mathbf{\overline A}$ ) = 1 - P(A)

P( $\mathbf{\overline A}$ ) = 1 - 2.493 × 10⁻⁷

P( $\mathbf{\overline A}$ ) = 0.9999997507

However, P(fatal accident over a lifetime) = P(at least 1 fatal accident in lifetime i.e. 46000 trips)

= 1 - P(NO fatal accidents in 46000 trips)

Similarly,

P(No fatal accidents over a lifetime) = P(No fatal accident in the 46000 trips) = P(No fatality on the 1st trip and No fatality on the 2nd trip ... and no fatality on the 45999 trip and no fatality on the 46000 trip)

= $[P(\overline A)] ^{46000} \ \ \ (since \ trips \ are \ independent \ events)$

= $[0.9999997507]^{46000}$

= 0.9885977032

Finally;

P(fatal accident over a lifetime) = 1 - 0.9885977032

P(fatal accident over a lifetime) = 0.0114022968

P(fatal accident over a lifetime) ≅ 0.0114

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