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3 years ago

13

Help with 10-13 ASAP. Explain your answer

1 answer:

erastova [34]3 years ago

7 0

From my understanding of the question you’re trying to find the value of k

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A=c+(-10) Solve for c in terms of other variables.

True [87]

To do this we need to move 10 to other side. To accomplish this you just need to add 10 to both side since (-10)

so
A+ 10 = c -10 + 10
we get
A+ 10 = c

lets say it wasn't -10 but positive 10.

A = c + 10 then we would subtract 10 from both sides

A -10 = c + 10 - 10
we get
A - 10 = C

5 0

3 years ago

2 and 1/3 + 1.5x = 12.3. What is x?

tangare [24]

(I'm not totally sure but there may be someone else with a more accurate/correct answer.)

Here is what I got (Red represents my work, blue represents to follow which steps and highlighter represents what the answer is):

3 0

4 years ago

I am a multiple of 70. I am between 500 and 1000. My tens digit is odd. What number could I be?

tamaranim1 [39]

Answer:

Step-by-step explanation:

490 = 70 * 7

560 = 70 * 8

630 = 70 *9

700 = 70 * 10

770

840

910

You can fill in the other 3

So the number can be 630 770 or 910

6 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST

Evgesh-ka [11]

Hello!

Her first commision would have to be multiplied by 5% first, which would be 6,000 x .05

This would equal to $300.

The second part would be .075 x 6000.

This equals to $450

Then, .01 x 12,000

This equals to $120.

Add all commisions, 300+450+120

****$870 is the total commision she received. ****

I hope I did this right. It's my first time on brainly. Tell me if you got it. Sorry if I didn't help

6 0

3 years ago

The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a

umka2103 [35]

Answer:

0.01265

Step-by-step explanation:

Since, if the time to be served has an exponential distribution with a mean of 7, then

$P(T < t_0) = 1 - e^{-\frac{t_0}{7}}$

Chance to be served in under 2 minutes:

$P(T$

Let A represents the number of days when a person is served in less than 2 minutes,

Hence,

the probability that a person is served in less than 2 minutes on at least 5 of the next 7 days ( using binomial distribution )

= P(A=5) + P(A=6) + P(A=7)

$=^7C_5(0.249)^5(1-0.249)^2+^7C_6(0.249)^6(1-0.249)^1+^7C_7(0.249)^7(1-0.249)^0$

$=\frac{7!}{2!5!}(0.249)^5(1-0.249)^2+\frac{7!}{1!6!}(0.249)^6(1-0.249)^1+\frac{7!}{0!7!}(0.249)^7(1-0.249)^0$

≈ 0.01265

5 0

3 years ago