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Juli2301 [7.4K]
4 years ago
11

The figure is the net for a rectangular prism.

Mathematics
2 answers:
bekas [8.4K]4 years ago
6 0
Start with a right rectangular prism as shown below and call the length l, the width w, and the height h:



In order to make a rectangular prism like the one shown above, you basically use the following rectangular prism template:



Looking at the rectangular prism template, it is easy to see that the solid has six sides and each side is a rectangle

The bottom side and the top side are equal and have l and w as dimensions

The area for the top and bottom side is l× w + l × w = 2 × l × w

The front side (shown in sky blue) and the back side (not shown) are equal and have h and l as dimensions

The area for the front and the back side is l× h + l × h = 2 × l × h

Then, the last two sides have h and w as its dimensions. One side is shown in purple

The area for the front and the back side is w× h + w × h = 2 × w × h

The total surface area, call it SA is:

<span>SA = 2 × l × w  +  2 × l × h  +  2 × w × h </span>


Example #1:

<span>Find the surface area of a rectangular prism with a length of 6 cm, a width of 4 cm, and a height of 2 cm </span>

<span>SA = 2 × l × w  +  2 × l × h  +  2 × w × h </span>

<span>SA = 2 × 6 × 4  +  2 × 6 × 2  +  2 × 4 × 2 </span>

<span>SA = 48 + 24 + 16 </span>

SA = 88 cm2


Example #2:

<span>Find the surface area of a rectangular prism with a length of 4 cm, a width of 5 cm, and a height of 10 cm </span>

<span>SA = 2 × l × w  +  2 × l × h  +  2 × w × h </span>

<span>SA = 2 × 4 × 5  +  2 × 4 × 10  +  2 × 5 × 10 </span>

<span>SA = 40 + 80 + 100 </span>

SA = 220 cm2


Example #3:

<span>Find the surface area with a length of 1/2 cm, a width of 8 cm, and a height of 1/4 cm </span>

<span>SA = 2 × l × w  +  2 × l × h  +  2 × w × h </span>

<span>SA = 2 × 1/2 × 8  +  2 × 1/2 × 1/4  +  2 × 8 × 1/4 </span>

<span>SA = 1 × 8  +  1 × 1/4  +  16 × 1/4 </span>

SA = 8 + 1/4 + 4

<span>SA = 12 + 1/4 </span>

<span>SA = 48/4 + 1/4 </span>

SA = 49/4 cm2<span> SA = 12.25 cm</span>2 

<span />

here is the answer hope it helps 


kolbaska11 [484]4 years ago
4 0

The answer to this question is 238 mm^2

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The (x,y) values for the position of the ship after completing its first heading are:

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The trigonometric angle for the second heading is <span><span>θ2</span>=<span>90∘</span>−<span>90∘</span>=<span>0∘</span></span>

The (x,y) values for the position of the ship after completing its second heading is:

<span>x=<span>(10.4mi)</span><span>cos<span>(<span>56∘</span>)</span></span>+<span>(4.6mi)</span><span>cos<span>(<span>0∘</span>)</span></span>≈10.4mi</span>
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The bearing angle is:

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