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xxMikexx [17]
3 years ago
15

Respond to the following in three to five sentences. Select the workplace skill, habit, or attitude described in this chapter th

at you believe is most important for being a successful employee. Explain your choice.
Computers and Technology
2 answers:
Serjik [45]3 years ago
8 0

A skilled and successful worker is any worker who has special skill, training, knowledge, and (usually acquired) ability in their work. A skilled worker may have attended a college, university or technical school. Or, a skilled worker may have learned their skills on the job. Examples of skilled labor include engineers, software development, paramedics, police officers, soldiers, physicians, crane operators, truck drivers, machinist, drafters, plumbers, craftsmen, cooks and accountants. These workers can be either blue-collar or white-collar workers, with varied levels of training or education.

1. They Think About the Skills They Need for the Next Job

We all (OK, most of us) try to be awesome at the skills in our job descriptions, but the most successful people also focus on what they’ll need to know to succeed in their next jobs. Not sure what skills you should be developing? Check out career expert Laura Katen’s tips for honing in on exactly what to reach for next.

2. They Speak Up in Meetings

Especially if you’re in a large meeting, intimidated by the higher-ups there, or don’t know much about what’s going on, it’s easy to sit tight and listen. But the people who get ahead don’t wait for permission or an invitation to speak—they make sure everyone in the room knows they have something to contribute. Even if you don’t have a suggestion? “Speaking up to advocate for a co-worker’s point of view or asking a well thought-out question can go just as far,” says leadership coach Jo Miller.

3. They Dress for the Job They Want

You’ve heard it a thousand times—but it consistently holds true. People who get ahead at work look to those above them and emulate not only the clothes they wear, but the ways in which they present themselves in the office, interact with others, and approach their work.

4. They Get to Know the Higher-Ups

It’s pretty hard to get promoted if your boss’ boss doesn’t know who you are—so make it a point to get to know the higher-ups in your department. Check out Sara McCord’s tips for talking to your boss’ boss the right way.

5. They Know How to Communicate With Those Higher-Ups

If you’ve ever been in an executive-level meeting, you know that c-suiters communicate a bit differently than the rest of us. So, if you want to make it there someday, it’s key to learn how to talk the talk. Career coach Lea McLeod gives a few tips for getting started.

DENIUS [597]3 years ago
6 0

I feel like the best workplace skill described in this chapter is initiative. Without initiative, all the other workplace skills aren't important. Everyone needs initiative in order to be a successful employee. Initiative shows that you are motivated to have the job and will be dependable when needed.

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Answer:

The answer is option d.

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3 years ago
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The following checksum formula is widely used by banks and credit card companies to validate legal account numbers: d0 + f(d1) +
Aleksandr [31]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to import Scanner class

public class ISBN

{   public static void main(String[] args)  { // start of main() function body

   Scanner s = new Scanner(System.in); // creates Scanner object

//prompts the user to enter 10 digit integer

   System.out.println("Enter the digits of an ISBN as integer: ");    

   String number = s.next(); // reads the number from the user

   int sum = 0; // stores the sum of the digits

   for (int i = 2; i <= number.length(); i++) {

//loop starts and continues till the end of the number is reached by i

          sum += (i * number.charAt(i - 1) ); }

/*this statement multiplies each digit of the number with i and adds the value of sum to the product result and stores in the sum variable*/

          int remainder = (sum % 11);  // take mod of sum by 11 to get checksum  

   if (remainder == 10)

/*if remainder is equal to 10 adds X at the end of given isbn number as checksum value */

  { System.out.println("The ISBN number is " + number + "X"); }

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// displays input number with the checksum value computed

 {System.out.println("The ISBN number is " + number + remainder); }  }  }  

Explanation:

This program takes a 10-digit integer as a command line argument and uses Scanner class to accept input from the user.

The for loop has a variable i that starts from 2 and the loop terminates when the value of i exceeds 10 and this loop multiplies each digit of the input number with the i and this product is added and stored in variable sum. charAt() function is used to return a char value at i-1.

This is done in the following way: suppose d represents each digit:

sum=d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9

Next the mod operator is used to get the remainder by dividing the value of sum with 11 in order to find the checksum and stores the result in remainder variable.

If the value of remainder is equal to 10 then use X for 10 and the output will be the 10 digits and the 11th digit checksum (last digit) is X.

If the value of remainder is not equal to 10, then it prints a valid 11-digit number with the given integer as its first 10 digits and the checksum computed by sum % 11 as the last digit.  

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Which is a feature of audio editing software?
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Will give brainliest and good amount of points, no false answers.
nlexa [21]

The problem with the swap function is that it loses the value at the first index, as soon as it gets overwritten by the value at the second index. This happens in the first statement. To fix it, you need a helper variable.

First you're going to "park" the index at the first index in that helper variable, then you can safely overwrite it with the value at the second index. Then finally you can write the parked value to the second index:

var swap = function(array, firstIndex, secondIndex) {

let helper = array[firstIndex];

array[firstIndex]  = array[secondIndex];

array[secondIndex] = helper;

};

I hope this makes sense to you.

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