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sashaice [31]
3 years ago
5

PLS HELP!!! BRAINLIEST AND 50 POINTS!!!!! CORRECT ANSWERS ONLY PLS What is the value of x?

Mathematics
1 answer:
Vinil7 [7]3 years ago
8 0

Answer:

x = 27

Step-by-step explanation:

39/26 = x /18

cross multiply

26x = (39)(18)

26x = 702

x = 27

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A scale factor of 1 will produce a congruent image​
horsena [70]

Answer:

no factor of one

Step-by-step explanation:

If the scale factor is greater than 1, the image is an enlargement (a stretch). If the scale factor is between 0 and 1, the image is a reduction (a shrink). If the scale factor is 1, the figure and the image are congruent. The word "dilate" is often heard in relation to the human eye.

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3 years ago
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For what value of p will the pair of linear equations have infinitely many solutions (p-3)x + 3y = p , px+ py = 12
sleet_krkn [62]

Answer: p = 6


Step-by-step explanation:

HI !


 px + 3y - ( p-3)=0


a₁ = p , b₁ = 3 , c₁ = - (p-3)


=====================


12x + py - p=0


a₂ = 12  , b₂ = p , c₂ = -p


since , the equations have infinite solutions , 


a₁/a₂ = b₁/b₂ = c₁/c₂


p/12 = 3/p =  p-3/p



--------------------------------------


p/12 = 3/p


cross multiply ,


p² = 36


p = √36

 p = 6


for the value of p = 6 , the equations will have infinitely many solutions





5 0
3 years ago
Jane has 5 nickels. john has 3 dimes. jane says she has a greater amount of money. with the information given, is she correct?
joja [24]
No Jane is not correct she has 25 cents where john has 30 cents
7 0
3 years ago
Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
Vaselesa [24]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0
3 years ago
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