Answer:
yes -5 is greater than -10 because on a timeline -5 comes before -10
which means its greater
6 sides, 7 length for one side
6x7 = 42 for the first one
52 for one side, has 5 sides
52x5 = 260 for the second.
Answer:
x = 28 (So it takes 28 hours for the temperature to reach 0°C.)
y = -70 (So the temperature when the experiment begins is −70°C.)
Step-by-step explanation:
To find the the x value, you remove the y value or replace it with 0.
0 = 5/2x - 70
Next you move the variable.
70 (2/5) = x (multiply 70 by 2 to get 140 and divide that by 5)
And now you simplify to get:
28
To find the y value, you remove the x value or replace it with 0.
y = 0 - 70
And now you simplify to get:
-70
x = 28
y = -70
Answer:
Answers provided below
Step-by-step explanation:
From the simultaneous linear equation, we have the coefficient matrix as;
(3 4 5)
(2 -1 8)
(5 -2 7)
The x-matrix is Dx is given by;
(18 4 5)
(13 -1 8)
(20 -2 7)
Similarly, the y-matrix Dy is given by;
(3 18 5)
(2 13 8)
(5 -20 7)
Also,the z-matrix Dz is given by;
(3 4 18)
(2 -1 13)
(5 -2 -20)
Determinant of the coefficient matrix from online determinant calculator is;
D = 136
Determinant of the x-matrix from online determinant calculator is; Dx = 92
Determinant of the y-matrix from online determinant calculator is; Dy = 696
Determinant of the z-matrix from online determinant calculator is; Dz = 576
From crammers rule;
x = Dx/D = 92/136
y = Dy/D = 696/136
z = Dz/D = 576/136
Answer: Third Choice. Thousandths
Step-by-step explanation:
<u>Concept:</u>
Here, we need to know the order and name of each place value.
Please refer to the attachment below for the specified names.
<u>Solve:</u>
<em>STEP ONE: Orde and name each place</em>
2 ⇒ One Thousands
4 ⇒ Hundreds
5 ⇒ Tens
6 ⇒ Ones
.
1 ⇒ Tenths
3 ⇒ Hundredths
8 ⇒ One Thousandths
7 ⇒ Ten Thousandths
<em>STEP TWO: Find the number [8] in the number</em>
As we can see from the list above, 8 is at the right of the decimal point, thus, the place value is <u>Thousandths</u>.
Hope this helps!! :)
Please let me know if you have any questions
