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Tasya [4]
3 years ago
11

What percent of 20 is 36

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
7 0
36 is more than 20 so the percentage is more than a hundred and less than 200% since 36 is less than 40. So if u subtract 20 from 36 and find that 16 is 80% of 20 and so when you add 100% to it, its 180%
vladimir2022 [97]3 years ago
4 0
20% * r = 36 
20/100 * r = 36 
20/100 * 100/20 *r = 36 * 100/20 
r = 36 * 100/20 = 36 * 5 = 180 
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What is the sale price to the nearest cent? $239 television; 10% discount
miv72 [106K]

Answer:

The sale price will be:  $215.10

Step-by-step explanation:

We know that:

Sale price = Regular price × (100% - Discount %)

                 = Regular price × (100% - 10%)

                 = 239 × 90%

                 = 239 × 0.9

                 = 215. 10 $

Therefore, the sale price will be:  $215. 10        

3 0
2 years ago
I think it is A but i am not sure can someone check and tell me if im wrong
nordsb [41]

Answer: it is 1.8

Step-by-step explanation: you can look up this same qustion and find it on branly <3 your right

7 0
2 years ago
best answer will be awarded the brainliest and 5 stars please evaluate 6/2 and remember to show your work
Svet_ta [14]
6/2 is the number 6 being divided in half by 2; to figure this out just count your 2 table factors! Shown work:

2 x 2 = 4
2 x 3 = 6!

So 6 divided by 2 (6/2) is just the oppoposite of 2 x 3 = 6
8 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
2 years ago
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What statement about a rhombus is never true?
Alekssandra [29.7K]
It can never be a square.
7 0
3 years ago
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