Answer:
A
Step-by-step explanation:
Answer:
A)2100 ml
Step-by-step explanation:
Given total vinegar is 3 1/2 liters and the used vinegar is 3/5 of the vinegar in the beaker:
#First calculate the amount of vinegar not poured in the beaker:
![V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}](https://tex.z-dn.net/?f=V_o%3DV_t-V_b%5C%5C%5C%5C%3D3%5Cfrac%7B1%7D%7B2%7D%281-%5Cfrac%7B2%7D%7B3%7D%29%5C%5C%5C%5C%3D1%5Cfrac%7B1%7D%7B6%7D)
#Calculate amount of vinegar used in experiment:
![V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}](https://tex.z-dn.net/?f=V_b%3D%5Cfrac%7B2%7D%7B3%7DV_t%3D%5Cfrac%7B2%7D%7B3%7D%283%5Cfrac%7B1%7D%7B2%7D%29%3D2%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5CV_u%3D%5Cfrac%7B3%7D%7B5%7DV_b%3D%5Cfrac%7B3%7D%7B5%7D%5Ctimes%202%5Cfrac%7B1%7D%7B3%7D%3D1%5Cfrac%7B2%7D%7B5%7D)
#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:
![V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml](https://tex.z-dn.net/?f=V_r%3DV_t-V_u%5C%5C%5C%5C%3D3%5Cfrac%7B1%7D%7B2%7D-1%5Cfrac%7B2%7D5%7D%5C%5C%5C%5C%3D2%5Cfrac%7B1%7D%7B10%7D%5Ctimes%201000%5C%20ml%5C%5C%5C%5C%3D2100%5C%20ml)
Hence, the unused vinegar is 2100 ml
Answer: 9/10 times
Step-by-step explanation:
Hi, to answer this question we simply have to divide 18/25 by 4/5
Mathematically speaking:
18/25 ÷ 4/5 = (18 x 5) / (25 x 4) = 90/100 = 9/10
In conclusion, the answer is 9/10 times.
Feel free to ask for more if needed or if you did not understand something.
The required diameter of dwarf planet is
.
<h3>What is a statement?</h3>
A statement is a declarative sentence that is either true or false but not both. A statement is sometimes called a proposition. The key is that there must be no ambiguity. To be a statement, a sentence must be true or false, and it cannot be both.
Given:
The given statement is the diameter of 3 planet is
planet A=
= 1000000000m
planet B=
=10000000m
planet C=
=100000000m
According to given question we have
A dwarf planet is discovered with a radius is 1/100 times of radius of planet C.
Radius of planet C =100000000/2= 50000000m
Radius of dwarf planet = 1/100 times of radius of planet C.
Radius of dwarf planet = 1/100 * 50000000m
Radius of dwarf planet = 500000 m=![5*10^{5} m](https://tex.z-dn.net/?f=5%2A10%5E%7B5%7D%20m)
Diameter of dwarf planet =2*500000 m=1000000 m=![10^{6} m](https://tex.z-dn.net/?f=10%5E%7B6%7D%20%20m)
Therefore, the required diameter of dwarf planet is
.
Learn more details about statement here:
brainly.com/question/2285414
#SPJ1
Answer:
it is 23.
Step-by-step explanation:
The hypotenuse has to be each leg added together which is 44. And 44 - 21 is 23.
Pls mark brainliest.