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ElenaW [278]
4 years ago
12

I need help please!!

Mathematics
1 answer:
Nitella [24]4 years ago
5 0

Answer:

\sqrt[12]{55296}  / 2

Third option

Step-by-step explanation:

∜6  /  ∛2

=  ∜6  × ∛ 2^2 /  ∛2 × ∛ 2^2

=  ∜6 × ∛4  / 2

= \sqrt[12]{6^3}  * \sqrt[12]{4^4}/2

= \sqrt[12]{216 * 256}/2

= \sqrt[12]{55296}/ 2

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3 years ago
Complete the square on the following quadratic x2+10x+9=0
kakasveta [241]
Given a quadratic equation x^{2} +ax+c=0

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.

In our case the coefficient of x is 10, so we write 10 as 2*5

2. then we write + 5^{2} and - 5^{2} to the expression:

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Answer:

= 4.32 × 10^4

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(thousand; prefix kilo- (k))

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Answer:

Less

Step-by-step explanation:

8 0
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