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4 years ago

I need help please!!

Mathematics

1 answer:

Nitella [24]4 years ago

5 0

Answer:

$\sqrt[12]{55296} / 2$

Third option

Step-by-step explanation:

∜6 / ∛2

= ∜6 × ∛ 2^2 / ∛2 × ∛ 2^2

= ∜6 × ∛4 / 2

= $\sqrt[12]{6^3} * \sqrt[12]{4^4}/2$

= $\sqrt[12]{216 * 256}/2$

= $\sqrt[12]{55296}/ 2$

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4x+15=75 in a number line

Dennis_Churaev [7]

Answer:

x= 15

Step-by-step explanation:

4x+15=75

4x = 60

x = 15

7 0

3 years ago

Seriously need help with this question or I will fail my senior year

nlexa [21]

Answer:

you cheater

Step-by-step explanation:

Tring to cheat because you don't feel like doing it. Hopefully you fail so you can learn your lesson

5 0

3 years ago

Read 2 more answers

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

3 years ago

Help please for today

miskamm [114]

Answer:

y: (0 , 2.5)

x: (3.5 , 0)

Step-by-step explanation:

Y-intercept : (0 , 2.5)

X-intercept: (3.5 , 0)

When looking at the intersection on the y-axis, the x-coordinate will be 0. And when looking at the intersection on the x-axis, the y-coordinate will be 0.

8 0

3 years ago

Write in slope intercept form the equation of a line that has the slope of 1/3 and the y- intercept of 5.

ludmilkaskok [199]

Answer:

y = 1/3x + 5

Step-by-step explanation:

Slope intercept form is y = mx + b

m is the slope

b is the y intercept

plug your number in

y = 1/3x + 5

5 0

3 years ago