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ElenaW [278]
4 years ago
12

I need help please!!

Mathematics
1 answer:
Nitella [24]4 years ago
5 0

Answer:

\sqrt[12]{55296}  / 2

Third option

Step-by-step explanation:

∜6  /  ∛2

=  ∜6  × ∛ 2^2 /  ∛2 × ∛ 2^2

=  ∜6 × ∛4  / 2

= \sqrt[12]{6^3}  * \sqrt[12]{4^4}/2

= \sqrt[12]{216 * 256}/2

= \sqrt[12]{55296}/ 2

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9x^3+6x^2-3x Please!!! HELP!!! need it done asap
Igoryamba

Step-by-step explanation:

9x^3+6x^2-3x

Cannot be simplified because there are no like terms but can be factored as

=3x(3x−1)(x+1)

8 0
3 years ago
1 point
irga5000 [103]

Answer:

show us the graphs to be able to tell you which one

Step-by-step explanation:

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3 years ago
Question 9 Of 1000 randomly selected cases of lung cancer, 841 resulted in death within 10 years. Construct a 95% two-sided conf
givi [52]

Answer:

0.818335 ≤ p ≤ 0.86366

Step-by-step explanation:

Given that:

Sample size (n) = 1000

Positive lung cancer = 841

n(p) = 841, p(p) = 841/1000 = 0.841

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1 - p = 0.159

95% confidence interval

For a 95% confidence interval : z = 1.96

P ± z√p(1-p) / n

0.841 ± 1.96 * √0.841(0.159) / 1000

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0.841 + (1.96 * 0.0115636) = 0.863664656

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4 0
3 years ago
I need help I try Photomath I didn’t help me .
kaheart [24]

Answer:

8. 8.80

9. 90

Step-by-step explanation:

Question 8: Use the Pythagorean formula

DE² = DF²+EF²

EF² = DE² - DF²

= 16.2² - 13.6²

= 77.48

EF = √77.48 = 8.80  (Answer)

Question 9: Use the Cosine Rule

GI² = GH² +HI² - 2·GH·HI·Cos ∠GHI

= 60² + 42² - 2·60·42·Cos 123

= 3600 +1764 - (-2744.98)

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4 0
3 years ago
Read 2 more answers
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serg [7]

The First group i.e 1-10 include more prime numbers .(2,3,5,7,1)

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  • Like 15 consists of 3×5

7 0
3 years ago
Read 2 more answers
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