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harina [27]
3 years ago
10

adam put $100 in a savings account after 10 years he had $1649 in the account what rate of interest did he earn? use the formula

a=pe^rt where a is the ending amount p is the principal (initial amount) r is the interest rate and t is the time
Mathematics
2 answers:
Nady [450]3 years ago
7 0
Using the formula
ending amount is 1649=a
p=initial amount=100
t=10
r=r

so
1649=100e^{10r}
divide both sides by 100
16.49=e^{10r}
take ln of both sides
ln(16.49)=10r
divide both sides by 10
(ln(16.49))/10=r
use calculator
0.28027=r
about 28% interest
stira [4]3 years ago
4 0
To fill in the equation would look like this:

1649 = 100e^(10r)


I then divided both side by 100 then use logs to help me solve from there resulting in the answer of about 28.0%
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Find an equation for the nth term of the arithmetic sequence.
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Answer:

The equation of the nth term is an = -621 + 42n

Step-by-step explanation:

* Lets revise the arithmetic sequence

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- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….

# 5  ,  10  ,  15  ,  20  ,  …………………………

# 12  ,  10  ,  8  ,  6  ,  ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

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, n is the position of the term

* Lets solve the problem

∵ an = a + (n - 1)d

∴ a14 = a + (14 - 1)d

∴ a14 = a + 13d

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- Similar we can find another equation from a15

∵ a15 = a + (15 - 1)d

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∴ a + 14d = 9 ⇒ (2)

- We will solve equations (1) and (2) to find a and d

* Lets subtract equation (2) from equation (1)

∴ (a - a) + (13 - 14)d = (-33 - 9)

∴ -d = -42 ⇒ × both sides by -1

∴ d = 42

- Substitute this value of d in equation (1) or (2)

∵ a + 13d = -33

∵ d = 42

∴ a + 13(42) = -33

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* Now lets write the equation of the nth term

∵ an = a + (n - 1)d

∵ a = -579 and d = 42

∴ an = -579 + (n - 1) 42 ⇒ open the bracket

∴ an = -579 + 42n - 42

∴ an = -621 + 42n

* The equation of the nth term is an = -621 + 42n

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