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svetoff [14.1K]
3 years ago
13

A circuit contains four resistors connected in series. R1 is 100 , R2 is 200 , R3 is 240 , and R4 is 600 . What is the total cir

cuit resistance?
Computers and Technology
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

1140Ω

Explanation:

For resistors in series, you can add their values.

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You can configure switch ports on default VLAN under normal operations. Cisco switches always have VLAN 1 as the default VLAN, which is required for many decorum communications between switches like spanning-tree protocol for example. It is obligatory not to delete or even change the default VLAN.

 

 





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A Java main method uses the parameter (String[ ] variable) so that a user can run the program and supply "command-line" paramete
xxTIMURxx [149]

Answer:

True

Explanation:

Java and some other object oriented programs makes use of the command line arguments. This enables one to pass additional information to a program when it is run. whatever information that is passed to the program at the command line argument will accompany the program when is it run and java stores this information as an array of strings.

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Create a program that displays a menu to select addition, subtraction, or multiplication. Using random numbers between 0 and 12
Lemur [1.5K]

Answer:

This question is answered using C++

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

   int ope, yourresult;

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

   cout<<"Operator: ";

   cin>>ope;

   srand((unsigned) time(0));

   int num1 = rand() % 12;

   int num2 = rand() % 12;

   int result = 1;

   if(ope == 1){

       cout<<num1<<" + "<<num2<<" = ";

       result = num1 + num2;

   }

   else if(ope == 2){

       cout<<num1<<" - "<<num2<<" = ";

       result = num1 - num2;

   }

   else if(ope == 3){

       cout<<num1<<" * "<<num2<<" = ";

       result = num1 * num2;

   }

   else{

       cout<<"Invalid Operator";

   }

   cin>>yourresult;

   if(yourresult == result){

       cout<<"Correct!";

   }

   else{

       cout<<"Incorrect!";

   }

   return 0;

}

Explanation:

This line declares operator (ope) and user result (yourresult) as integer

   int ope, yourresult;

This prints the menu

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

This prompts the user for operator

   cout<<"Operator: ";

This gets user input for operator

   cin>>ope;

This lets the program generates different random numbers

   srand((unsigned) time(0));

This generates the first random number

   int num1 = rand() % 12;

This generates the second random number

   int num2 = rand() % 12;

This initializes result to 1

   int result = 1;

If the operator selected is 1 (i.e. addition), this prints an addition operation and calculates the actual result

<em>    if(ope == 1){</em>

<em>        cout<<num1<<" + "<<num2<<" = ";</em>

<em>        result = num1 + num2;</em>

<em>    }</em>

If the operator selected is 2 (i.e. subtraction), this prints an subtracttion operation and calculates the actual result

<em>    else if(ope == 2){</em>

<em>        cout<<num1<<" - "<<num2<<" = ";</em>

<em>        result = num1 - num2;</em>

<em>    }</em>

If the operator selected is 3 (i.e. multiplication), this prints an multiplication operation and calculates the actual result

<em>    else if(ope == 3){</em>

<em>        cout<<num1<<" * "<<num2<<" = ";</em>

<em>        result = num1 * num2;</em>

<em>    }</em>

If selected operator is not 1, 2 or 3, the program prints an invalid operator selector

<em>    else{</em>

<em>        cout<<"Invalid Operator";</em>

<em>    }</em>

This gets user input

   cin>>yourresult;

This checks if user result is correct and prints "Correct!"

   if(yourresult == result){

       cout<<"Correct!";

   }

If otherwise, the program prints "Incorrect!"

<em>    else{</em>

<em>        cout<<"Incorrect!";</em>

<em>    }</em>

   return 0;

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Answer: Hello!

Network Interface Card (NIC)

Explanation:

Mark me brainest please. Hope I helped! Hope you make an 100%

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Position that allows for professional growth and advancement

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