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Vesna [10]
3 years ago
7

7 1/8 is equal to greater than or less than 7.025

Mathematics
1 answer:
Sauron [17]3 years ago
4 0
7 1/8 is greater than 7.025
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Help!! Can someone explain this to me I’m not getting it.
chubhunter [2.5K]

Answer:

A. 99 sq cm

Step-by-step explanation:

Area of geometric shape

= 2 times the area of one triangle with base a and height c

+ 2 times the area of one triangle with base c and height b

+ Area of rectangle with dimensions a and c.

= 2 \times  \frac{1}{2} ac + 2 \times  \frac{1}{2} bc + ac \\  \\  = ac + bc + ac \\  \\  = 2ac + bc \\  \\  = 2(13)(3) + 7(3) \\  \\  = 78 + 21 \\  \\  = 99 \: sq \: cm

3 0
3 years ago
Read 2 more answers
I really need help. What is the answer?
coldgirl [10]

Answer:

4 units

Step-by-step explanation:

3-2=1 unit

7-3=4 units

1*4=4 units

7 0
3 years ago
13. which inequality has the following graphed solution?
mafiozo [28]
B. You have to solve for X, and graph using whatever is less than or greater than. 4x + 12 < 4 to 4x < -8 to x < -2.
5 0
3 years ago
Pls help!!!!The probability of hitting a target on a single trial is 40%,Find the probability of hitting the same target 5/8 tim
azamat
Probability hit=40%=4/10
probability no hit=1-p (hit)=1-4/10=6/10
probability= p(hit)+p(hit)+p(hit)+p(hit)+p(hit)+p (no hit)+p (no hit)+p (no hit)
probability=4/10×4/10×4/10×4/10×4/10×6/10×6/10×6/10
=0.0022
( I think but I'm not 100% sure)
6 0
3 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)
Romashka [77]

Answer:

The amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

Step-by-step explanation:

The given function is

f(t)=-\frac{1}{2}\sin (3t-2\pi)      .... (1)

The general form of sine function is

F(t)=A\sin (Bt-C)+D                 ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

A=-\frac{1}{2}

B=3

C=2\pi

D=0

So,

amplitude=|A|=\frac{1}{2}

period=3

\text{phase shift}=\frac{2\pi}{3}

Therefore amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

8 0
4 years ago
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