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3 years ago

What is the definition of infinite solutions?

Mathematics

1 answer:

Maurinko [17]3 years ago

5 0

Answer: A is the correct answer I am 100% positive

Step-by-step explanation:

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What two number multiply to negative 20 and add to 19

OLEGan [10]

$x;\ y-the\ numbers\\\\ \left\{\begin{array}{ccc}xy=-20\\x+y=19&\Rightarrow&x=19-y\end{array}\right\\\\subtitute\ to\ first\ equation:\\\\(19-y)y=-20\\19y-y^2+20=0\\-y^2+19y+20=0\ \ \ |change\ signs\\y^2-19y-20=0\\y^2-20y+y-20=0\\y(y-20)+1(y-20)+0\\(y-20)(y+1)=0\iff y-20=0\ or\ y+1=0\\\\y=20\ or\ y=-1$

$x=19-y\\\\for\ y=20\Rightarrow x=19-20=-1\\\\for\ y=-1\Rightarrow x=19-(-1)=20\\\\Answer:\boxed{\boxed{20\ and\ -1}}$

4 0

3 years ago

Find the set of values of x for which y is zero in the equation y=(x + 2) (2x-2)

Alex777 [14]

Answer:

{ - 2, 1 }

Step-by-step explanation:

To determine the values let y = 0, that is

(x + 2)(2x - 2) = 0 ← in standard form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

2x - 2 = 0 ⇒ 2x = 2 ⇒ x = 1

The set of values are { - 2, 1 }

8 0

3 years ago

Find the measure of

Korolek [52]

Answer:

105°

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which sentence

shepuryov [24]

Recycling can help reduce garbage, but items such as disposable diapers cannot be recycled.

The landfill, along with many other considerations, is paying the price for our practice in over population. We have spent our immense wealth on sex and reproduction and convenience with the result of things like diapers which, once used, cannot be recycled. It is a point really well taken. We cannot keep on filling our land and oceans with products that cannot be disposed of any other way. We need to be considering alternate ways of accomplishing the same thing.

7 0

3 years ago

Find all solutions to the equation in the interval [0,2pi]. Enter the solutions in increasing order. sin 2x = sin x

Nastasia [14]

Step-by-step explanation:

$sin2x=sinx\\sin2x-sinx=0\\2*sinx*cosx-sinx=0\\sinx*(2*cosx-1)-0\\sinx=0 \\x=\pi n\ \ \ \ \ x\in[0;2\pi ]\ \ \ \ \Rightarrow\\x_1=0\ \ \ \ x_2=\pi .\\2*cosx-1=0\\2*cosx=1\ |:2\\cosx=\frac{1}{2} \\x=б\frac{\pi }{3} +2\pi n\ \ \ \ \ x\in[0;2\pi ]\ \ \ \ \Rightarrow\\x_3=\frac{\pi }{3} \ \ \ \ \ x_4=\frac{5\pi }{3}.\\$

$Answer: x=0,\ \frac{\pi }{3} ,\ 1\pi ,\ \frac{5\pi }{3} .$

3 0

2 years ago