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Licemer1 [7]
3 years ago
13

Change 0.61 into a fraction

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0

Answer:

61/100 or sixty-one hundredths

Step-by-step explanation:

<u>0</u>.61

The numbers on the left of the decimal point represent whole numbers in a decimal, and so they do in a fraction. Since there is a 0 in the left side, there is no whole number.

0.<u>61</u>

The numbers on the right of the decimal point are tenths, hundredths, and thousandths, meaning they represent the number out of the whole number.

In a fraction, that would be the numerator because it represents the numbers that go into the denominator, which is the place value.

stiks02 [169]3 years ago
3 0
The answer to your question is 61/99
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The triangle and square have equal perimeters. What is the perimeter of the triangle?
Bezzdna [24]

Answer:

E. 16

Step-by-step explanation:

Perimeter of the triangle = 4x+4x+(x+7)

Perimeter of square = 4(x+3)

We know that the perimeters are equal so we can form an equation to solve for x:

9x+7 = 4x + 12

Now we can subtract 4x from both sides to move the xs to the left side, and the same with the 7 so we have the variable on one side and the constant on the other:

9x+7-7-4x=12+4x-4x-7

5x = 5

Now we divide both sides by 5 to get:

5x/5 = 5/5

x = 1

Now we can use this value to figure out the perimeter of the triangle:

P = 9x + 7

x=1, substitute into equation:

P = 9(1) + 7

P = 16

Hope this helped!

6 0
2 years ago
PLEASE HELPP PLEASEE
notka56 [123]

Answer:

Step-by-step explanation:

762=330(1+0.11)^{n}

n=8.02

6 0
3 years ago
What is 5% added to $194?
leva [86]

Answer:

203.7

Step-by-step explanation:

5% of 194 added to 194 =

= 5% * 194 + 194

= 0.05 * 194 + 194

= 9.7 + 194

= 203.7

6 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is upper s equals { 1 comma 2 comma 3 comma 4
Softa [21]

You can think of this experiment as follows: you have to select a random number between 1 and 15, where each number is equally likely to appear.

Player A wins if 3,4,5 or 6 are picked.

Player B wind is 10,11 or 12 are picked.

Two events are said to be mutually​ exclusive if they cannot happen at the same time. So, in our metaphor, the question is: can we pick a particular number, so that both players win simultaneously?

The question is no, because if player A wins, we have picked 3,4,5 or 6, and player B wins with none of these numbers.

Similarly, if player B wins, we have picked 10, 11 or 12, and player A wins with none of these numbers.

So, the two events cannot occur simultaneously.

If you want to be more formal, since the events are subset of the sample space, two events are mutually exclusive if their intersection is the empty set, and this is the case:

A \cap B = \{3,4,5,6\}\cap\{10,11,12\} = \emptyset

8 0
3 years ago
Graph the line using intercepts: 4x-3y=12
Furkat [3]
First you have to find the intercepts!

To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).

Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).

So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.

hope that helped~

8 0
3 years ago
Read 2 more answers
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