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Arturiano [62]
3 years ago
13

Bob measured a restaurant and made a scale drawing. The scale of the drawing was 8 millimeters = 4 meters. What is the drawing's

scale factor?
Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

meter =1,000 millimeters. So, the scale is:

7 mm:1,000 mm Divide both sides by 7

1 mm:142 6/7 mm - This is the scale that Tess used.

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If x2+1/x2=18, find the value of x3−1/x3
Elden [556K]

Answer:

There are 2 answers : 76 or -76

Step-by-step explanation:

x^2+\dfrac{1}{x^2} =18\\\\(x-\dfrac{1}{x} )^2=x^2+\dfrac{1}{x^2} -2=18-2=16\\\\x-\dfrac{1}{x}=4\ or\ x-\dfrac{1}{x}-4\\\\(x-\dfrac{1}{x} )^3=x^3-\dfrac{1}{x^3} -3x^2*\dfrac{1}{x}+3x*\dfrac{1}{x^2}\\\\=x^3-\dfrac{1}{x^3}-3(x-\dfrac{1}{x})\\\\x^3-\dfrac{1}{x^3}=(x-\dfrac{1}{x} )^3+3(x-\dfrac{1}{x})\\\\if\ x-\dfrac{1}{x}=4\ then \ x^3-\dfrac{1}{x^3}=4^3+3*4=64-12=76\\\\if\ x-\dfrac{1}{x}=-4\ then \ x^3-\dfrac{1}{x^3}=(-4)^3+3*(-4)=-64-12=-76\\\\

7 0
3 years ago
Read 2 more answers
I need help. Please give me an example
xxTIMURxx [149]

Answer:

9

Step-by-step explanation:

3/729= 9

729=9^3

=3/9^3= 9


Hope this helps! Please give brainiest!

8 0
4 years ago
Based on data, here is a regression line comparing the variables y = mass of a bar of soap in grams and x = number of days soap
Irina18 [472]

Answer:

D .For every day the soap is used, the predicted mass of the soap will decrease by 1.8 grams.

Step-by-step explanation:

The given regression equation is

Predicted y = 78.5 – 1.8x where,  y = mass of a bar of soap in grams and x = number of days soap has been used.

Here, slope=b=-1.8.

Slope depicts the unit increase in predicted variable due to change in independent variable.

The given slope -1.8 shows that due to change in number of days soap is used the predicted mass of the soap decreases by 1.8 units. So, we can say that "For every day the soap is used, the predicted mass of the soap will decrease by 1.8 grams".

4 0
4 years ago
May I have some help with these, please?
Nookie1986 [14]

Minimum = 18, Q₁ = 27.5, median = 39.5, Q₃ = 43, maximum = 49.

The five-number summary is a descriptive statistic that provides information on a series of observations. It consists of the following statistics:

1. Minimum: the smallest observation

2. First quartile  Q₁: the average of the values ​​below the median.

3. Medium  M: the average term.

4. third quartile  Q₃: the average of values ​​above the median.

5. Maximum: The largest observation.

The data represents the numbers of runs allowed by 8 college pitchers.

{18, 49, 38, 41, 33, 44, 42, 22}

The five-number summary is:

First, we have to sort the data from least to greatest.

{18, 22, 33, 38, 41, 42, 44, 49}

From the ordered data we can see that the minimum value is 18 and the maximum is 49.

The median is the middle term of the data set. In this case of an even number of terms, the median is the average of the terms located in the middle. So, the terms located in the middle if the data are in bold:

{18, 22, 33, 38, 41, 42, 44, 49}

Median= (38 + 41)/2 = 79/2 = 39.5

To calculate the first quartile Q₁, the values ​​below the median are {18, 22, 33, 38}. So, the median of this values is the first quartile Q₁:

{18, 22, 33, 38}

Q₁ = (22 + 33)/2 = 55/2 = 27.5

To calculate the third quartile  Q₃, the values ​​above the median are {41, 42, 44, 49}. So, the median of this values is the third quartile Q₃:

{41, 42, 44, 49}

Q₃ = (42 + 44)/2 = 86/2 = 43

8 0
3 years ago
Consider the parallelogram.
maks197457 [2]

Answer: 25

Step-by-step explanation: first find x; 60= 10x - 10, then subtract 10 from both sides to get 50, then divide by 5 to get 10, then plug it in to the equation of the side to get 25

4 0
3 years ago
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