What is the distance between (2, -1) and (-1, -5) on the coordinate plane? 7 units 6 units 5 units 4 units

1 answer:

3 0

You can use the distance formula:
<span> $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
<span>
Plug in the given coordinates:
</span><span> $\sqrt{(-5-2)^2 + (-1+1)^2}$

$\sqrt{(7)^2 + (0)^2}$

$\sqrt{49+0}$

$\sqrt{49}=7$

Final answer : 7units
</span></span>

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Please help as soon as possible <br>it's due tomorrow

erma4kov [3.2K]

Answer:

378 cm^3

Step-by-step explanation:

V = Bh = l * w * h

since the Base B is 54 (l*w), multiply by 7 to find volume

54 * 7 = 378

7 0

3 years ago

A ladder that is 13 meters long is leaning against a wall. The distance between the foot of the ladder and the wall is 7 meters

Maksim231197 [3]

<h2>Answer:</h2>

The equation that is used to model the length of ladder in terms of x is:

$x^2-7x-60=0$

<h2>Step-by-step explanation:</h2>

We can model this problem with the help of a right angled triangle whose hypotenuse is 13 meters and the other two legs are x meters and (x-7) meters.

where x is the distance between the top of the ladder and the ground.

and (x-7) is the distance between the foot of the ladder and the wall.

Hence, using Pythagorean Theorem we have:

$13^2=x^2+(x-7)^2\\\\i.e.\\\\169=x^2+x^2+49-14x\\\\i.e.\\\\169=2x^2-14x+49\\\\i.e.\\\\2x^2-14x+49-169=0\\\\i.e.\\\\2x^2-14x-120=0\\\\i.e.\\\\x^2-7x-60=0$