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AveGali [126]
4 years ago
9

In a bank account a paid out expense is called a debit and a deposit is called a credit. Would you use positive or negative inte

gers to represent credits? Debits? Explain.
Mathematics
1 answer:
Allisa [31]4 years ago
5 0

Answer:

positive integer

Step-by-step explanation:

In a bank account,

A paid out expense is called as debit

A deposit is called as credit

To find: sign used to represent credits

Solution:

Integers denote a set of natural numbers, their negative counterpart, and 0.

As credit denotes the amount deposited, the positive integer is used to denote credits.

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ANSWER QUICK!! 75 PTS!!!
iogann1982 [59]

Answer:

2) x = -2 , y = 2

3) no solution exists

Step-by-step explanation:

Solve the following system:

{-2 x - 3 y = -2

y = 2 x + 6

Hint: | Perform a substitution.

Substitute y = 2 x + 6 into the first equation:

{-2 x - 3 (2 x + 6) = -2

y = 2 x + 6

Hint: | Expand the left hand side of the equation -2 x - 3 (2 x + 6) = -2.

-2 x - 3 (2 x + 6) = (-6 x - 18) - 2 x = -8 x - 18:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Isolate terms with x to the left hand side.

Add 18 to both sides:

{-8 x = 16

y = 2 x + 6

Hint: | Solve for x.

Divide both sides by -8:

{x = -2

y = 2 x + 6

Hint: | Perform a back substitution.

Substitute x = -2 into the second equation:

Answer: {x = -2 , y = 2

4 0
3 years ago
Compare the line passing through the points (−3, −11) and (6, 4) to the line given by the equation y=35x−6.
Aleks04 [339]
Let
<span>A------> (−3, −11)
B------>  (6, 4)

step 1
find the slope m point A and point B
m=(y2-y1)/(x2-x1)-----> </span>m=(4+11)/(6+3)----> m=15/9---> 5/3

step 2
with m=5/3 and point B (6, 4)  find the equation of a line
y-y1=m*(x-x1)-----> y-4=(5/3)*(x-6)---> y=(5/3)x-6

case <span>a. they have the same slope------> is not correct
because
</span><span>y=35x−6------> the slope m=35
</span>y=(5/3)x-6---> the slope m =5/3

case <span>b. they have the same x-intercept.----> is not correct
because
</span>the x-intercept is for y=0

y=35x−6-----> 0=35x-6----> 35x=6-----> x=6/35
the x-intercept is the point (6/35,0)

y=(5/3)x-6----> 0=(5/3)x-6----> (5/3)x=6---> x=18/5
the x-intercept is the point (18/5,0)

case <span>c. the two lines are perpendicular. do. they have the same y-intercept-----> is nor correct
because

if two lines are perpendicular
m1*m2=-1-------> </span><span>this condition is not satisfied
</span>
the y intercept is for x=0

y=35x−6-------> y=-6
the y intercept is the point (0,-6)

y=(5/3)x-6-----> y=-6
the y intercept is the point (0,-6)

 they have the same y-intercept but the two lines are not perpendicular

see the attached figure

7 0
3 years ago
4. A loan made on March 12 is due September 10 of the following year. Find the exact time for the loan in a non-leap year and a
saul85 [17]

Answer:

182 days

Step-by-step explanation:

Given:

Date on which loan is made = March 12

Due date of the loan = September 10

Now,

The months in between March and September and the number of days in the particular months are

Month                          Number of days

April                               30

May                                31

June                               30

July                                 31

August                            31

------------------------------------------

Total number of days =  153

also,

Number of days left in March after 12 are (31 - 12 ) = 19 days

and,

Number of days in September before the due date = 10 days

Hence, the total time for loan = 19 + 153 + 10 = 182 days

since the included months does not have the month of February. Therefore,

the time for both leap year and non-leap year will remain same.

7 0
4 years ago
Find the inequality represented in the graph.
Digiron [165]

Answer: y > -1/2x + 2

Step-by-step explanation: first, in order to find the inequalities you should find the gradient by choosing two points from the line and you should you the formula m=y2-y1/x2-x1 to find the gradient.

Next, you should find the y-intercept in order to complete the inequality it can be easily found as the y-intercept is the place where the line crosses the y axis

Then you create your equation { y = -1/2x + 2 } and then if above the line is shaded then it is {> greater than} and if below the line is shaded then it should be {< less than}

(so you should replace the equation with the lesser or greater sign according to the way the graph is shaded)

7 0
2 years ago
Which rule can you use to find the nth term of an arithmetic sequence in which the common difference is 5 and a12 = 63?
iren2701 [21]
Tn = a + (n-1)d

when n  = 12, tn  = 63

63 = a + (12-1)*5

a = 63 - 55 =8

tn or an 
= 8 + (n-1) 5

=  3 + 5n

Hope this helps
4 0
4 years ago
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