Answer:
4c^2+7c-5=0
4c^2+7c=5
4c^2+7c=5
4c^2+7c-5=0\quad :\quad c=\frac{-7+\sqrt{129}}{8},\:c=\frac{-7-\sqrt{129}}{8}\quad \left(\mathrm{Decimal}:\quad c=0.54472\dots ,\:c=-2.29472\dots \right)
Hope This Helps!!!
If you graph out y = x^2 - 1, you'll see that it is a curved parabola. It is not a straight line. So visually this shows the equation is not linear. It's considered nonlinear.
Algebraically, the given equation does not fit the form y = mx+b which is slope intercept form. So this is more confirmation that we do not have a linear function.
Lemme think bout it....no
Step-by-step explanation:
Not entirely sure, but I believe something like this:
∠1 + ∠2 = 180° since they are a linear pair;
Since ∠1 = ∠2, we can say:
∠1 + ∠1 = 180°
2(∠1) = 180°
∠1 = 90°
And since:
∠1 = ∠2
∠2 = 90°
So the angle between t and s is 90°;
An angle of 90° means t and s are perpendicular (⊥)
to be differentiable, it necessarily has to be continuous. For this condition to be met, we need
and 
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