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antiseptic1488 [7]
3 years ago
11

Draw the segment PQ with endpoints P(-2, -1) and Q(2,4) on the coordinate plane. Then find the length and midpoint of PQ.

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

The graph of the line segment PQ is attached. To find the length, we have to use distance formula which is

d = \sqrt{ (x_{2} -x_{1} )^2 + (y_{2} - y_{1} )^2  }

PQ = \sqrt{ (2-(-2))^2 + (4- (-1))^2 } = \sqrt{ (2+2)^2 + (4+1)^2 }

PQ = \sqrt{16+25} = \sqrt{41}

To find the midpoint,we have to use the formula

( \frac{x_{1}+ x_{2} }{2} ,\frac{y_{1}+ y_{2} }{2} ) = (\frac{-2+2}{2} , \frac{-1+4}{2} )

= ( \frac{0}{2} , \frac{3}{2} ) = (0 , \frac{3}{2} )

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Dennis_Churaev [7]

Answer: 17/7

Step-by-step explanation: Step 1: Simplify both sides of the equation. y+4/15 + 2y−5/5 = 2/5 1/15 y+ 4/15 + 2/5 y+−1= 2/5 (Distribute) ( 1/15 y+ 2/5 y)+( 4/15 +−1)= 2/5 (Combine Like Terms) 7/15 y+ −11/15 = 2/5 7/15 y+ −11/15 = 2/5 Step 2: Add 11/15 to both sides. 7/15 y+ −11/15 + 11/15 = 2/5 + 11/15 7 15 y= 17/15

7 0
2 years ago
Angles A and B are supplementary. The measure of angle A is 60° and the measure of angle B is represented by 3x. Which equation
boyakko [2]
B
because the angles are supplementary meaning they add up to 180
5 0
3 years ago
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Vsevolod [243]
The answer is 10 miles
3 0
2 years ago
What are the coordinates of the vertex of the graph of the absolute value function h(x) = 3|x + 5| + 2? A) (5,-2) B) (-5,2) C) (
saw5 [17]

Answer:

B) Vertex = (-5, 2)

Step-by-step explanation:

Vertex can be defined as defined as the point where two lines meet and form a particular angle with each other. It can also be described as the point where a line changes its direction

We can find vertex by two methods:

<h3>1) GRAPH</h3>

We can see in the graph attached below that the line changes its direction at point (-5, 2). So the vertex is (-5,2)

<h3>2) FORMULA</h3>

General form of equation of mod function is given by

y = a |x - h| + k

where Vertex = (h, k)

The given equation is

h(x) = 3 |x + 5| + 2

h(x) = 3 |x - (-5)| + 2

where h = -5 and k = 2

So the vertex is:

Vertex = (-5, 2)

7 0
3 years ago
Please help with 3 questions and show all work!!!
sergeinik [125]
Question 1:
Since the triangles are congruent, we know that QS = TV
This means that 
3v + 2 = 7v - 6
Subtract both sides by 2
3v = 7v - 8
Subtract 7v from both sides
-4v = -8
Divide both sides by -4
v = 2
Plug this value back into 3v + 2 and you get 8.
QS = 8
Since the triangles are congruent
QS = 8    AND    TV = 8

Question 2:
So we know that AC = AC because that's a shared side.
It's also given that BC = CD.
In order for two triangles to be congruent by SAS, the angle between the two sides must be congruent.
That means angle C must be congruent to angle C from the other triangle.

Question 3:
We know that AC = AC because it's a shared side.
We also know that angle A from one triangle is equal to angle C from the other.
However, for a triangle to be congruent by SAS, the congruent angle must be between two congruent sides. 
In order for us to prove congruence by SAS, AD must be congruent to BC.

Have an awesome day! :)
3 0
2 years ago
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