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Mrac [35]
2 years ago
9

A man on the third floor of a building shouts down to a person on the street. If the man is 25 feet up and the distance between

the person on the street and the man in the building is 50 feet, what is the angle of elevation (in degrees) between the person on the street and the person in the building?
Mathematics
2 answers:
Inga [223]2 years ago
7 0
Heellloooo

the answer is about 57

Have anice day
gladu [14]2 years ago
3 0
Tan^(-1) = 25/50
= 26.56 degrees
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6 0
3 years ago
Read 2 more answers
Please help me ASAP
elena-14-01-66 [18.8K]

Answer:

∠ 1 = 123°

Step-by-step explanation:

One way

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 1 is an external angle of the triangle, thus

∠ 1 = 90° + 33° = 123°

Second way

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 given angles from 180 for third angle in Δ

third angle = 180° - (90 + 33)° = 180° - 123° = 57°

The third angle and ∠ 1 form a straight angle and are supplementary, thus

∠ 1 = 180° - 57° = 123°

7 0
3 years ago
Use the distributive property to solve the equation -9(x+5)=27
Yuliya22 [10]
The answer is x = -8. Hope this helps!
3 0
2 years ago
Your job is to sort and sack marbles for sale. A bag contains 55 marbles, some red and some green. If there are 11 red marbles,
vovikov84 [41]
Total of 55 marbles.....if there are 11 red marbles, then there are (55 - 11) = 44 green marbles. So the ratio of red marbles to green marbles is :
11:44 which reduces to 1:4 or 1/4 or 1 to 4
5 0
3 years ago
Read 2 more answers
An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth
sattari [20]
They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east.  Then we can say that there positions, y and x are:

y=150-600t  x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)


7 0
3 years ago
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