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dusya [7]
3 years ago
14

A consulting firm submitted a bid for a large research project. The firm's management initially felt there was a 60/40 chance of

getting the bid. However, the agency to which the bid was submitted subsequently requested additional information on the bid. Experience indicates that on 70% of the successful bids and 35% of the unsuccessful bids the agency requested additional information. If required, round your answers to two decimal places. a. What is the prior probability that the bid will be successful (i.e., prior to receiving the request for additional information)b. What is the conditional probability of a request for additional information given that the bid will ultimately be successful?c. Compute the posterior probability that the bid will be successful given a request for additional information.
Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Answer:

Step-by-step explanation:

Given Probability that bid will be unsuccessful = 0.35

a) What is the prior probability that the bid will be successful ;

= 1 - P(unsuccessful) = 1 - 0.35

= 0.65

b) What is the conditional probability of a request for additional information given that the bid will ultimately be successful = 0.70

c) Compute the posterior probability that the bid will be successful given a request for additional information ; Applying Baye's theorem ;

P(S|AI) = P(S) X P(AI|S) / P(S) X P(AI|S) + P(Unsuccessful) x P(AI|S)

= 0.65 X 0.70 / 0.65 X 0.70 + 0.35 X 0.35

= 0.6125

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Alex

Answer:

\frac{1}{5} ,  \frac{1}{3} , \frac{4}{6}.

Step-by-step explanation:

Given fractions \frac{1}{3}, \frac{4}{6}, \frac{1}{5}.

We need to list them from least to greatest.

In order to arrange them from least to greatest, we need to find the least common denominator of  \frac{1}{3}, \frac{4}{6}, \frac{1}{5}.

We have 3, 6 and 5 in denominators.

Least common multiple of 3, 6 and 5 is = 30, because 30 is least number that can be divided by all three number 3, 6 and 5.

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Multiplying first fraction \frac{4}{6} by 5 in top and bottom, we get

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Multiplying first fraction  \frac{1}{5} by 6 in top and bottom, we get

\frac{1}{5} = \frac{1\times6}{5\times6}=\frac{6}{30}.

Now, we can check \frac{10}{30}, \frac{20}{30} \ and \ \frac{6}{30}.

\frac{6}{30} is the smallest, \frac{10}{30} is greater and \frac{20}{30} is the greatest.

Therefore, we can arrange fractions\frac{6}{30}, \frac{10}{30} \ and \ \frac{20}{30}.

Writing original fractions in place of equivalent fractions, we can write

\frac{1}{5} ,  \frac{1}{3} and  \frac{4}{6}.

Therefore, the order the amounts of paint from least to greatest is:

\frac{1}{5} ,  \frac{1}{3} , \frac{4}{6}.




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