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Keith_Richards [23]
3 years ago
7

What is wrong with the equation? π 4 sec(θ) tan(θ) dθ = 4 sec(θ) π π/3 = −12 π/3 There is nothing wrong with the equation. f(θ)

= 4 sec(θ) tan(θ) is not continuous on the interval [π/3, π] so FTC2 cannot be applied. f(θ) = 4 tan(θ) is not continuous on the interval [π/3, π] so FTC2 cannot be applied. f(θ) = 4 sec(θ) is not continuous at θ = π/3 so FTC2 cannot be applied. The lower limit is not equal to 0, so FTC2 cannot be applied.
Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

if f(θ) = 4 is true then print"hello" elif print "ues'

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Answer:

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Step-by-step explanation:

|a+x|/2 − |a−x|/2 , if a=−2; x=−6

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Simply plug in the numbers

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Answer:

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Step-by-step explanation:

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