1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Keith_Richards [23]
3 years ago
7

What is wrong with the equation? π 4 sec(θ) tan(θ) dθ = 4 sec(θ) π π/3 = −12 π/3 There is nothing wrong with the equation. f(θ)

= 4 sec(θ) tan(θ) is not continuous on the interval [π/3, π] so FTC2 cannot be applied. f(θ) = 4 tan(θ) is not continuous on the interval [π/3, π] so FTC2 cannot be applied. f(θ) = 4 sec(θ) is not continuous at θ = π/3 so FTC2 cannot be applied. The lower limit is not equal to 0, so FTC2 cannot be applied.
Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

if f(θ) = 4 is true then print"hello" elif print "ues'

You might be interested in
Help me with ma work pls
Serga [27]
Simply you would do

45+10 time the number of days

So

45+10 x 2 and then you would put the answer in the next Collin
5 0
3 years ago
Read 2 more answers
Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)
maxonik [38]

Answer with Step-by-step explanation:

We are given that

r(t)=< t^2,\frac{2}{3}t^3,t >

We have to find T,N and B at the given point t > (1,2/3,1)

r'(t)=

\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1

T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}

Now, substitute t=1

T(1)=\frac{}{2+1}=\frac{1}{3}

T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}

T'(1)=-\frac{4}{9}+\frac{1}{3}

T'(1)=\frac{1}{9}=

\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}

N(1)=\frac{T'(1)}{\mid T'(1)\mid}

N(1)=\frac{}{\frac{2}{3}}=

N(1)=

B(1)=T(1)\times N(1)

B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}

B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})

B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k

B(1)=\frac{1}{3}

5 0
3 years ago
A ruler is 12 inches long.what is the length of this ruler in centimeters
lawyer [7]
I think it is 30.48 because i looked it up 
8 0
4 years ago
Read 2 more answers
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
3 years ago
Jeremy earned $33,000 after working for 44 weeks. How much money did Jeremy earn each week? Show Your Work
dmitriy555 [2]

Answer: jimmy needs a new job

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • How many millimeters are in 15 fluid ounces
    8·1 answer
  • When Jared found 1/5 +2/5,he wrote the sum 3/10 is Jared correct
    14·2 answers
  • Write the base number for each expression: Please I need with steps
    10·1 answer
  • What is 3/4 +3/5 as a mixed number
    13·2 answers
  • Solve the equation<br><br> 90= -20x <br> Plz help
    7·2 answers
  • 8,382 ÷ 7 divides enter you're answering by filling in these boxes
    8·1 answer
  • A ride-sharing company claims that the cost of rides follows a Normal distribution with a mean of $10.52. After
    13·1 answer
  • Pls, help I don't wanna get a bad grade pls:)
    7·2 answers
  • Helpppppppppppppppppppppppppppp
    8·2 answers
  • Solve this inequality algebracially. |3-x|&gt;10
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!