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Mrac [35]
3 years ago
8

In vietnam, business relationships are often based on

Business
2 answers:
emmainna [20.7K]3 years ago
7 0
A
social networks
 vietnam is a communist state. Factors of production are communally owned by the communities or by the state.
Agata [3.3K]3 years ago
5 0

Answer:

Social networks

Explanation:

Business relationship in Vietnam depends largely on social relationship and network.It occurs through sharing of personal lifestyle , political and sports view . The interaction may not directly be connected to business but it could open up opportunities for business and even referrals.This means that someone with a very good and lively social life has a higher tendency of recording a good success in business.

The system make use of internet , calls ,email , brochures , advertisement , trade fair as media of propagating business  

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1 year ago
If the absence of an agreement to the contrary in partnership, what are the all partners entitled?
Ne4ueva [31]

Answer:

d) All of above​

Explanation:

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6 0
3 years ago
The Oxford Provident Building Association was the first ________ to form in America.
11Alexandr11 [23.1K]

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8 0
3 years ago
If a country's economy is to sustain long-run economic growth, the business environment must be conducive to the consistent prod
Aliun [14]

Answer:

True

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5 0
3 years ago
Stan wants to start an IRA that will have $250,000 in it when he retires in 25 years. How much should he invest semiannually in
Wittaler [7]
<span>25 years: No Payment, but total is 250000
6 months earlier. Payment of "P". It's value 1/2 year later is P(1+0.03)
6 months earlier. Payment of "P". It's value 1 year later is P(1+0.03)^2
6 months earlier. Payment of "P". It's value 1½ years later is P(1+0.03)^3
6 months earlier. Payment of "P". It's value 2 years later is P(1+0.03)^4

</span><span>We need to recognize these patterns. Similarly, we can identify the accumulated value of all 50 payments of "P". Starting from the last payment normally is most clear.
</span>
<span>P(1.03) + P(1.03)^2 + P(1.03)^3 + ... + P(1.03)^50
 That needs to make sense. After that, it's an algebra problem.
 P[(1.03) + (1.03)^2 + (1.03)^3 + ... + (1.03)^50]
</span>
P(<span><span>1.03−<span>1.03^51)/(</span></span><span>1−1.03) </span></span>= <span>250000</span>
8 0
4 years ago
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