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4 years ago

I need help on finding these angles ASAP

Mathematics

1 answer:

marishachu [46]4 years ago

8 0

regular Hexagons have angles of 120 degrees

if angle GHE= 90 degrees, angle GEH=60 degrees since its half of 120

since triangles add up to 180,

180-90=90

90-60=30

so question 2 is 30 degrees

question 3 is 60 degrees

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Suppose a square is 1/4. draw each of the following. 1,1 1/2, 2

Yuri [45]

You have to multiply 1/4 by something so you can get to the number that is telling you to draw.

5 0

3 years ago

An archery target consists of an inner circle and four concentric rings. The width of each ring is equal to the radius r of the

Karo-lina-s [1.5K]

Answer:

0.4

Step-by-step explanation:

Radius of inner circle = r

Radius of entire circle = r + r + r + r + r = 5r

Probability that an arrow hitting the target will land on inner circle ;

Area of inner circle / area of entire circle

Recall :

Area of circle = πr²

Hence ;

πr² / π(5r)² = πr² / π25r² = 1 / 25 = 0.4

4 0

3 years ago

A) What FRACTION is equal to 50% of 1/3?<br>b) what FRACTION is equal to 75% of 1/2

blondinia [14]

Step-by-step explanation:

a is 1/6

b is 3/8

i dont understand how though sorry my friend just told me the answers

6 0

3 years ago

Help thankss <br>answer is <br><img src="https://tex.z-dn.net/?f=%20%28%20-%2014.0%29" id="TexFormula1" title=" ( - 14.0)" alt="

lyudmila [28]

We have point $P=(x_0,y_0)=(2,-4)$ , so first calculate $f'(x_0)$ . There will be:

$y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}$

Now, we can write the equation of the normal line as:

$y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}$

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

$\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\
0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}$

8 0

3 years ago

In the first quarter of the game,the giants gained 5 yards,lost 13 yards,gained 2 yards,gained 6 yards and,unfortunately,lost 12

Luden [163]

Answer:

5 + (-13) + 2 + 6 + (-12) ;

-12 yards

Step-by-step explanation:

5 yards gain = + 5

13 yard loss = - 13

2 yards gain = + 2

6 yards gain = + 6

12 yards loss = - 12

Using addition Rule :

5 + (-13) + 2 + 6 + (-12)

The net yardage :

5 - 13 + 2 + 6 - 12 = - 12

Net yardage = - 12 yards

7 0

3 years ago