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victus00 [196]
3 years ago
5

Just need help on this question​

Mathematics
1 answer:
Aneli [31]3 years ago
8 0
It should be the first one I hope I’m right bro
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Marie get allowance everyday she gets 10$ each week she already has 30$ But she wants 90$ how much money does she need to make 9
Dima020 [189]

Answer:

She needs $60 more so she has to work 6 weeks to get that much.

Step-by-step explanation:

x = each week

y = total

Equation:

90 = 10x + 30

10x = 60

x = 6

7 0
4 years ago
Read 2 more answers
Surveys were sent to a random sample of owners of all-wheel-drive (AWD) vehicles and to a random sample of owners of front-wheel
salantis [7]

Answer:

No, the confidence interval does not provide evidence that this belief is plausible as the confidence interval range contains the null value (0)

Step-by-step explanation:

Given that the confidence interval for the mean difference of AWD and FWD vehicles is :

(−0.01,0.12)

When defining the hypothesis for mean difference :

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Using the confidence interval result, reject the Null if the confidence interval value at the given α - level does not contain 0 ; otherwise fail to reject the Null ;

Since the (−0.01,0.12) contains 0 ; then we fail to reject the Null and conclude that there is no statistically significant difference between the two groups

8 0
3 years ago
Part A A<br> Select the number that is greater<br> 15x15x15 or<br> 13x13x13<br> Help!
77julia77 [94]

Answer:

15x15x15

Step-by-step explanation:

13x13x13= 2197

15x15x15= 3375

6 0
3 years ago
Find the sum of 914 and 878
Cerrena [4.2K]
The word "sum" means addition, so the question is asking you to add 914 and 878.

First you can add the hundreds, so 900 + 800 = 1,700
Then you can add the tens, so 10 + 70 = 80
And finally the units, so 4 + 8 = 12
When you add up all of these, you get your final answer as 1,792.

I hope this helps!
3 0
3 years ago
Read 2 more answers
Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If
djyliett [7]

Answer:

Option a. 0.9811

Step-by-step explanation:

First, you need to use a normal distribution table to solve this. If you don't have it, then see the attached table so you can guide yourself.

Now, we want to know the probability of randomly select 75 women whose height have a mean between 63 and 65 inches, knowing that in general, the mean is 63.5 and standard deviation of 2.5

To do this, you should calculate first the Z score value for both heights, one for 63 inches and the other with 65 inches. Then, with those values, we'll look the table to get the area under the curve, and thus, the probability. To calculate Z use the following expression:

Z = x - μ / (σ/√n)

Where:

μ: mean height

σ: standard deviation

x: height required

n: sample population

We have all the data so let's calculate both values of Z:

Z1 = 63 - 63.6 / (2.5/√75) = -2.08

Z2 = 65 - 63.6 / (2-5/√75) = 4.85

With these Z score, let's watch the table, and see which area belongs to,

In the case of Z1, the area is 0.0188, while Z2 is 1.

To know the probability, all we need to do is substract those values:

P = 1 - 0.0188 = 0.9812

Option a) is the most accurate and closest result to this.

5 0
4 years ago
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