The equivalent ratio is 1/4
the number of degree in the central angle
For the given function, we have:
Domain: (-∞, ∞)
Range: [-2, ∞)
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How to find the domain and range of the given function?</h3>
Remember that for a function the domain is the set of the possible inputs while the range is the set of the outputs.
On the graph, we can see a quadratic equation, remember that for every polynomial the domain is the set of all the real values, the same is for this case, so we conclude that the domain is:
D: (-∞, ∞)
The range will be the set of all values larger than the minimum of the parabola, which is at the vertex.
On the graph, we can see that the minimum is y = -2, then the range is:
R: [-2, ∞)
If you want to learn more about range and domains:
brainly.com/question/10197594
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Answer:
(sin x)^2*(sec x) is positive in QII
Step-by-step explanation:
(sin x)^2 is always 0 or positive. Here x lies in QII.
sec x is positive when the adjacent side is positive and negative when the adjacent side is negative. In QII the adjacent side is positive.
In summary, (sin x)^2*(sec x) is positive in QII
Answer: $48
Step-by-step explanation:
Principal×Rate×Time
$300×2/100×8yrs
