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2 years ago

A triangle has a perimeter of 10a + 3b + 12 and has sides of length 3a + 8 and 5a + b what is the length of the third side ?

Mathematics

1 answer:

RideAnS [48]2 years ago

5 0

Answer:

2a +2b +4

Step-by-step explanation:

The perimeter is the sum of the lengths of the three sides. If x represents the length of the third side, then ...

(3a +8) +(5a +b) +x = (10a +3b +12)

Subtracting from the equation everything on the left side that is not x, we get ...

x = (10a +3b +12) -(3a +8) -(5a +b)

= a(10 -3 -5) +b(3 -1) +(12 -8)

= 2a +2b +4

The length of the third side is 2a +2b +4.

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Answer:

4/5

Step-by-step explanation:

-18/2 = -9, and integer
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2 years ago

What’s 4/5 of 3 And what’s 2/9 of 20

Karo-lina-s [1.5K]

Answer:

4/5 of 3 = 12/5

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Design a sine function with the given properties:

Rom4ik [11]

Answer:

$f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$ .

Step-by-step explanation:

Given information:

Period = 24 hr

Maximum = 16 at t=16 hr.

Minimum = 10 at t=4 hr.

The general sin function is

$y=A+\sin(B(x-C))+D$ .... (1)

where, |A| is altitude, $\frac{2\pi}{B}$ is period, C is phase shift and D is midline.

Period is 24 hr.

$24=\dfrac{2\pi}{B}\Rightarrow B=\dfrac{\pi}{12}$

Altitude is

$A=\dfrac{Maximum-Minimum}{2}=\dfrac{16-10}{2}=3$

$D=\dfrac{Maximum+Minimum}{2}=\dfrac{16+10}{2}=13$

The function is minimum at t=4 and maximum at t=16,phase shift is

$C=\dfrac{16+4}{2}=10$

Substitute these values in equation (1).

$y=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$

Therefore, the required function is $f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$ .

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2 years ago

A person draws a card from a hat. Each card is one color, with the following probabilities of being drawn: 1/25 for black, 1/5 f

Schach [20]

Step-by-step explanation:

P(black or yellow) = P(black) + P(yellow) − P(black and yellow)

P(black or yellow) = 1/25 + 1/5 − 0

P(black or yellow) = 6/25

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3 years ago