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posledela
3 years ago
6

A triangle has a perimeter of 10a + 3b + 12 and has sides of length 3a + 8 and 5a + b what is the length of the third side ?

Mathematics
1 answer:
RideAnS [48]3 years ago
5 0

Answer:

  2a +2b +4

Step-by-step explanation:

The perimeter is the sum of the lengths of the three sides. If x represents the length of the third side, then ...

  (3a +8) +(5a +b) +x = (10a +3b +12)

Subtracting from the equation everything on the left side that is not x, we get ...

  x = (10a +3b +12) -(3a +8) -(5a +b)

  = a(10 -3 -5) +b(3 -1) +(12 -8)

  = 2a +2b +4

The length of the third side is 2a +2b +4.

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