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posledela
3 years ago
6

A triangle has a perimeter of 10a + 3b + 12 and has sides of length 3a + 8 and 5a + b what is the length of the third side ?

Mathematics
1 answer:
RideAnS [48]3 years ago
5 0

Answer:

  2a +2b +4

Step-by-step explanation:

The perimeter is the sum of the lengths of the three sides. If x represents the length of the third side, then ...

  (3a +8) +(5a +b) +x = (10a +3b +12)

Subtracting from the equation everything on the left side that is not x, we get ...

  x = (10a +3b +12) -(3a +8) -(5a +b)

  = a(10 -3 -5) +b(3 -1) +(12 -8)

  = 2a +2b +4

The length of the third side is 2a +2b +4.

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To see the two rectangles in the picture, you can draw a line parallel to segment MR througn point N.

From the original picture you can state the dimensions of both rectangles.

Call S, the point where the line that you drew intercepts the segment RQ.

Then one rectangle is MNSR and the other rectangle is OPQS.

The measures of the sides of the rectangle MNSR are:

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So its area is base * height, which you can all A1.

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With this procedure you can tell the value needed.   

 
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