Question

A typical human cell is approximately 10.00 10.00 μm in diameter and enclosed by a membrane that is 8.000 8.000 nm thick. What is the volume of the cell including the membrane?

Answer 1

Answer:

$V_{cell =$ 526.12 μm³

Explanation:

Given that;

A typical human cell is approximately 10.00 μm in diameter    &

enclosed by a membrane that is 8.000 nm thick.

What is the volume of the cell including the membrane?

First, let's determine the radius of the human cell=

= $\frac{1}{2}*d$

= $\frac{1}{2}*10$

= 5 μm

Now, the radius of the cell including the membrane

= 5 μm + 8.000 nm

= 5 μm + 0.008 μm

= 5.008  μm

The volume of the cell including the membrane is given by the formula:

$V_{cell]= \frac{4}{3} *\pi *(r_{cell})^3 um^3$

$V_{cell = \frac{4}{3}*3.142*(5.008)^3um^3$

$V_{cell =$ 526.1160731 μm³

$V_{cell =$ 526.12 μm³