For the lever to work, your force multiplied by the input arm should be equal to the rock's weight multiplied by the output arm. Therefore:
500I = 2000O
I/O = 4
The input and output arms should be in the ratio 4 : 1
Answer:
B. The emission of high-energy particles or waves from atoms
Explanation:
2 gallons has to be the answer you know you can just look it up right lol
Answer:
a) The US power rating for the european bulb must be 27.27 W
b) The current in the United Stated for the european bulb is 0.227A
Explanation:
First of all the bulb is not going to light in 120V like it does in 220V, the bright is going to be much lower (near 1/4). Now, lets take a look on a circuit perspective:
The bulb in a circuit is modeled like a simple resistor, so we have a resistor conected to a voltage source, see figure 1. There we have a current
given by:
![I_{1}=\frac{V_{1} }{R}](https://tex.z-dn.net/?f=I_%7B1%7D%3D%5Cfrac%7BV_%7B1%7D%20%7D%7BR%7D)
Where
is the 220v Input voltage, R is the resistance from the bulb. In the problem we have the power consumption in watts given by:
![W_{1}= V_{1]*I_{1}](https://tex.z-dn.net/?f=W_%7B1%7D%3D%20V_%7B1%5D%2AI_%7B1%7D)
Clearing
![I_{1} =\frac{I_{1}}{W_{1} } =\frac{100}{220} =0.4545 A](https://tex.z-dn.net/?f=I_%7B1%7D%20%3D%5Cfrac%7BI_%7B1%7D%7D%7BW_%7B1%7D%20%7D%20%3D%5Cfrac%7B100%7D%7B220%7D%20%3D0.4545%20A)
Now, from ohm's law
![\frac{V_{1} }{I_{1} } =R=\frac{220 }{0.4545 }=484 ohm](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%20%20%7D%7BI_%7B1%7D%20%7D%20%3DR%3D%5Cfrac%7B220%20%20%7D%7B0.4545%20%7D%3D484%20ohm)
So 484 ohm is the resistance from the bulb.
Now in the circuit lets replace the voltage source from 220v to 120v and lets calculate the current, and the power consuptiom
![I_{2}= \frac{V_{2}}{R}=\frac{110}{484} =0.227 A](https://tex.z-dn.net/?f=I_%7B2%7D%3D%20%5Cfrac%7BV_%7B2%7D%7D%7BR%7D%3D%5Cfrac%7B110%7D%7B484%7D%20%20%3D0.227%20A)
And the power consuptiom:
![W_{2}= V_{2]*I_{2}=110*0.227=27.27Watts](https://tex.z-dn.net/?f=W_%7B2%7D%3D%20V_%7B2%5D%2AI_%7B2%7D%3D110%2A0.227%3D27.27Watts)
<h2>Answer: Because they rotate really fast.
</h2>
First, it is necessary to clarify what is a pulsar (pulsating star) and what is a neutron star:
<u>A pulsar</u> is a neutron star that emits very intense electromagnetic radiation at short and periodic intervals due to its intense magnetic field that induces this emission.
<u>A neutron star</u>, is the name given to the remains of a supernova. In itself it is the result of the gravitational collapse of a massive supergiant star after exhausting the fuel in its core.
Neutron stars have a small size for their very high density and they rotate at a huge speed.
<h2>So, the way to know that a pulsar is a neutron star is because of its <u>high rotating speed.
</u></h2>
Nevertheless, it is important to note that all pulsars are neutron stars, but not all neutron stars are pulsars.