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Natali [406]
3 years ago
11

How do we know that pulsars are neutron stars?

Physics
1 answer:
DiKsa [7]3 years ago
4 0
<h2>Answer: Because they rotate really fast. </h2>

First, it is necessary to clarify what is a pulsar (pulsating star) and what is a neutron star:

<u>A pulsar</u> is a neutron star that emits very intense electromagnetic radiation at short and periodic intervals due to its intense magnetic field that induces this emission.

<u>A neutron star</u>, is the name given to the remains of a supernova. In itself it is the result of the gravitational collapse of a massive supergiant star after exhausting the fuel in its core.

Neutron stars have a small size for their very high density and they rotate at a huge speed.

<h2>So, the way to know that a pulsar is a neutron star is because of its <u>high rotating speed. </u></h2>

Nevertheless, it is important to note that all pulsars are neutron stars, but not all neutron stars are pulsars.

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A rubber ball is dropped and bounces vertically from a horizontal concrete floor. If the ball has a speed of 3 m/s just before s
Ganezh [65]

Answer:

F=12.5N

Explanation:

Net force = rate of change of momentum

F = m*a

so find the change of momentum P

Pdown

P=m*v_1=0.42kg*3m/s

Pup

P=m*v_1=0.42kg*6.5m/s

dP = change in P

dP= 0.42kg (3- -.6.5)m/s =3.99 kg m/s

dT = 0.32 s

so

F = \frac{dP}{dt}=\frac{3.99Kg*m/s}{0.32s} =12.468 N

6 0
4 years ago
Which applied force will allow a 7.65 kg block of ice to begin sliding on a sheet of ice? The block of ice has a kinetic coeffic
Anni [7]

Answer:

force for start moving is 7.49 N

force for moving constant velocity 2.25 N

Explanation:

given data

mass = 7.65 kg

kinetic coefficient of friction = 0.030

static coefficient of friction = 0.10

solution

we get here first weight of block of ice that is

weight of block of ice = mass  ×  g

weight of block of ice = 7.65 × 9.8 = 74.97 N

so here Ff = Fa

so for force for start moving is

Fa = weight × static coefficient of friction  

Fa = 74.97 × 0.10

Fa =  7.49 N

and

force for moving constant velocity is

Fa =  weight × kinetic coefficient of friction

Fa = 74.97 × 0.030

Fa = 2.25 N

7 0
4 years ago
Read 2 more answers
The small currents in axons corresponding to nerve impulses produce measurable magnetic fields. a typical axon carries a peak cu
Gemiola [76]

Answer:

6.66\cdot 10^{-12}T

Explanation:

The magnetic field produced by a current-carrying wire is given by

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 is the vacuum permeability

I is the current

r is the distance from the wire

In this problem we have

I=0.040 \mu A=4\cdot 10^{-8}A

r = 1.2 mm = 0.0012 m

So the magnetic field strength is

B=\frac{(4\pi \cdot 10^{-7} H/m)(4\cdot 10^{-8}A)}{2\pi (0.0012 m)}=6.66\cdot 10^{-12}T

5 0
3 years ago
An interplanetary spacecraft is moving at
mixer [17]
The awnser is. 1728000 kilometers
7 0
3 years ago
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The mass of an object is 4kg and it has a density of 5gcm^-3. what is the volume ​
Andru [333]

Answer:

density =   mass/ volume

5=4000/ volume

volume=4000/5

volume=800 cm^-3

4 0
3 years ago
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