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Nastasia [14]
3 years ago
7

If the roots (x-2)^2=k are equal find the value of k

Mathematics
1 answer:
Olenka [21]3 years ago
6 0

(x-2)^2=k\\x^2-4x+4=k\\Let\:x^2-4x+4=0, so \:x=2=>\\k=0

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insens350 [35]
X²+35=0
X(x+35)=0

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-35 -35
X=-35

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What are two other ways to name EF
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Read 2 more answers
How to differentiate ?
Bas_tet [7]

Use the power, product, and chain rules:

y = x^2 (3x-1)^3

• product rule

\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}

• power rule for the first term, and power/chain rules for the second term:

\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}

• power rule

\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3

Now simplify.

\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) =  \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)

Differentiate both sides and you end up with the same derivative:

\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2

7 0
3 years ago
What are the two conditions that an asset of a business needs to fulfill?
Darina [25.2K]

Answer:

<h2>✒️Answer:</h2>

<u>Two conditions must be satisfied. First, the revenue must be earned, which typically means that the customer has received the good or service. Second, the revenue must have been realized or realizable, implying that the customer has paid or is expected to pay for the merchandise.</u>

Step-by-step explanation:

<h2>#CarryOnLearning</h2>

watch.some.anime

4 0
2 years ago
Circle O has a circumference of approximately 250 ft
Varvara68 [4.7K]

Answer:

80 feet

Step-by-step explanation:

c=d\pi

Substitute 250 in for circumference

250=\pid

Divide by \pi or 3.14

d=79.617...

So, the diameter is approximately 80 feet

Hope this helps! :)

8 0
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