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olasank [31]
3 years ago
11

Please help!! I don't get it!

Mathematics
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

64 times 7.5 and you will get your answer

Step-by-step explanation:

16*4=64

64*7.5=x

x is what you need to find

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Candice bought a pencil box, shown below, to take with her to school
Phoenix [80]

Answer:

50.75

Step-by-step explanation:

You Just have to multiply length - width - and height - and you're good to go!

5 0
3 years ago
Identify all of the following solutions of square root of x plus 14 end root plus 2 equals x.
BabaBlast [244]
\bf \sqrt{x+14}+2=x\implies \sqrt{x+14}=x-2\impliedby \textit{squaring both sides}
\\\\\\
(\sqrt{x+14})^2=(x-2)^2\implies x+14=x^2-4x+4
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0=x^2-5x-10\impliedby \textit{now, using the quadratic formula}
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x=\cfrac{5\pm\sqrt{(-5)^2-4(1)(-10)}}{2(1)}\implies x=\cfrac{5\pm\sqrt{25+40}}{2}
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x=\cfrac{5\pm \sqrt{65}}{2}\implies x=
\begin{cases}
\cfrac{5+ \sqrt{65}}{2}\\\\
\cfrac{5- \sqrt{65}}{2}
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5 0
3 years ago
Read 2 more answers
Write two different ratios equal to 6:30
FromTheMoon [43]
The answer is d dtunbfdrtuikngfetuungdruijgrresssaaaaaweerttyuuiioopllmnvcxsawr
4 0
3 years ago
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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
2 years ago
Need help with my Geometry, can someone help me with 4,5 and 10?
xz_007 [3.2K]
For questions 4 and 5, use laws of complementary and supplementary angles to find values of x. I'm not too sure about what question 10 is asking.

Hope I helped :)

6 0
3 years ago
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