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tangare [24]
4 years ago
7

"You discover a new species of snail, Biologica terificia, and find that its haploid number is 4 (n = 4). The somatic cells of B

iologica terificia are diploid. How many chromosomes are in a somatic cell of the snail in G1 phase?
Biology
1 answer:
Georgia [21]4 years ago
6 0

Answer:

8 chromosomes

Explanation:

Diploid state is when an organism have two set of chromosomes (2n) i.e. combination of two haploid (n) gametes containing one set of chromosome each. Sexually reproducing organisms whose somatic or body cells are diploid (2n) undergo meiosis to produce gametes or sex cells with haploid number (n).

Therefore, in the newly discovered Biologica terificia species of snail, if the haploid state (n) of their gametes is 4, then their diploid (2n) somatic cells must be 4 × 2 = 8.

The question specifies the chromosomal number at the G1 phase of Interphase. At this stage, the cell is preparing to undergo division by increasing in size and duplicating its organnelles but not yet its genetic material which is not until the next phase called S-phase. Hence, the chromosome number of somatic cells remain 8 at the G1 phase.

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3 years ago
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Explain the specific mechanisms that have allowed for diversity in organisms
kirill115 [55]

There are five mechanisms involve in diversity of organisms:

genetic drift, mutation, natural selection, gene flow and non random mating.

Explanation:

Genetic drift: It is a mechanism in which frequency of the allele changes within a population due to random sampling. It causes decrease in diversity in organism and can result in new species.

Mutation: Mutation in the genes is the most important reason of diversity.the change in DNA causes introduction of new alleles. Harmful mutations do not le species evolve by delimiting them from reaching sexual maturity.

Gene flow: The allele flow happens when a new gene is introduced into a population either by immigration or random mating. when two populations of same species share genes, variation occurs.

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There is a population where the frequencies of allele 1 and allele 2 are 0.7 and 0.3, respectively. Allele 1 has a selection coe
Lorico [155]

Answer:

0.8

Explanation:

There is a population where the frequencies of allele 1 and allele 2 are 0.7 and 0.3, respectively

Let's use GG to represent allele 1

Let's use gg to represent allele 2

So we can equally say that;

GG = p = 0.7

gg = q  = 0.3   ( from Hardy-Weinberg Equilibrium)

So, given that the selection coefficient = 0.2

We known that the cross between GG and gg will definitely results to (GG,Gg and gg)

Then the fitness of these genes can be represented as:

1 - s, 1 and 1 - t respectively.

Thus. the allele 1's genotype fitness can be determined as

= 1 - s    ( where s is the selection coefficient)

= 1 - 0.2

= 0.8

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