4 years ago

Answer please please please

Mathematics

2 answers:

marin [14]4 years ago

8 0

She raised $22 for the fundraiser.

Sloan [31]4 years ago

4 0

28 in total that's the answer

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Step-by-step explanation:

Given that:

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since $\Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)$

Then, it implies that:

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$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}$

$\mathbf{= \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}$

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