Which question do you need answered or both?
Answer:
Hope this will help you
Step-by-step explanation:

The correct answer is 4
1.5 (4+4) -3 = 9
4.5 ( 4-2) =9
Answer:
.05x + 30 < 60
Step-by-step explanation:
.05x + 30 < 60
.05 is the cost per text. Since we don't know how many text messages she sends, we have to use x to represent it. We know she pays $30 every month no matter what so, we can write .05x + 30. < means it has to be LESS than $60 NOT EQUAL TO, but less than.
I hope this helps you out!
Answer:
(f+g)(2) = 4
(f-g)(4) = 8
(f ÷g)(2) = 7
(f x g)(1) = 0
Step-by-step explanation:
We are given these following functions:


(f+g)(2)

At 

Then
(f+g)(2) = 4
(f-g)(4)

At x = 4

Then
(f-g)(4) = 8
(f ÷g)(2)

At x = 2

Then
(f ÷g)(2) = 7
(f x g)(1)

Then

So
(f x g)(1) = 0