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bija089 [108]
3 years ago
12

Write out the steps in solving 3/4 x 2 2/5

Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0
3/4 × 2 2/5

Turn 2 2/5 into an improper fraction.

2 2/5 = (5 × 2) + 2 = 12

So, 2 2/5 = 12/5

So, our new question is : 3/4 × 12/5

Multiply the numerators (top numbers) with one another.

Numerators : (3 × 12) = 36

Multiply the denominators (bottom numbers) with one another.

Denominators : (4 × 5) = 20

So, our answer is 36/20

However, we need this to be a mixed number.

So, how many times does 20 go into 36? Once!

So, Multiply 20 with 1, and then subtract that number from 36! :)

20 × 1 = 20

36 - 20 = 16

So, our answer is :

1 16/20

Then, you simplify it once more.

Divide the numerator and denominator by 4.

16 ÷ 4 = 4

20 ÷ 4 = 5

So, our final answer is 1 4/5


~Hope I helped!~
Tems11 [23]3 years ago
7 0
3/4 * 2 2/5
=3/4 * 12/5
=36/20
=18/10
=9/5
=1 4/5
 
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Answer:

a

    f'(t) is  negative

b

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c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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