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Schach [20]
3 years ago
15

The sum of the digits of a two-digit number is 13. The units digit is one more than twice the tens digit. Find the number, and..

.
The sum of the digits of a three-digit number is 6. The hundreds digit is twice the units digit, and the tens digit equals to the sum of the other two. Find the number.
Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
8 0

Answer:

1)49

2)231

Step-by-step explanation:

1)

4+9=13

4*2=8

8+1=9

2)

2+3+1=6

2+1=3

1*2=2

wolverine [178]3 years ago
8 0

Answer:

#1. 49 #2. 231

Step-by-step explanation:

#1. 4 x 2 + 1 =

8 + 1 =

9

add 40 + 9 = 49

#2. x + 2x + (x + 2x) = 6

6x = 6  

x = 1  

2x = 2

x + 2x = 3  

(2 x 100) + (3 x 10) + 1 or 231.

Can I get Brainliest☺☺☺☺

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Step-by-step explanation: hope it helps

6 0
2 years ago
G(x) = 60(1 - 0.5)^x, g(4) *<br><br><br> Please do answer step by step
Flura [38]

Answer:

3.75

Step-by-step explanation:

g(x)=60(1-0.5)^x, g(4)

g(4)=60(1-0.5)^4

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7 0
2 years ago
Need some math help!!! <br> Factor the polynomial by grouping: 12p^3 − 21 p^2 + 28p − 49
Andru [333]

Answer:

\left(4p-7\right)\left(3p^2+7\right)

Step-by-step explanation:

12p^3-21p^2+28p-49

\left(12p^3-21p^2\right)+\left(28p-49\right)

7\left(4p-7\right)

3p^2\left(4p-7\right)

7\left(4p-7\right)+3p^2\left(4p-7\right)

\left(4p-7\right)\left(3p^2+7\right)

8 0
2 years ago
Read 2 more answers
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

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5 0
2 years ago
The dimensions of a rectangle can be given by x+7 and x+2. If the area of the rectangle is 66 square inches, what are the dimens
Nadusha1986 [10]

to solve  for the dimensions (x+7)(x+2)=66,

we can first use the foiling method to simplify the left side.

x^2 + 2x + 7x + 14 = 66

x^2 + 9x + 14 = 66

now, subtract 66 from both sides.

x^2 + 9x - 52 = 0

now, split this into two parentheses.

(x + 13)(x - 4)

since the root of -13 would give you negative values, x=4. This means that the dimensions of the rectangle are 11 and 6.

7 0
2 years ago
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