Hello,
A good method for solving this question is creating an equation to solve for the width of the door.
Let w = the width of the door
Let h = the height of the door
The height (h) is twice the width (2w) and one foot more (+1).
We can make the equation h = 2w + 1
Now, we are given that the height of the door is 7 feet, so h = 7.
We can simply plug in 7 for h in the equation to solve for w.
So, we have h = 2w + 1
7 = 2w + 1
Subtract by 1 on both sides to get:
6 = 2w
Divide by 2 on both sides to get:
w = 3
The width of the door is 3 feet.
However, we should check out answer with the given question to make sure it checks out.
We are given that the height of the door is one foot more than twice its width, and the height of the door is 7 feet.
Twice the width is 6 feet, and one foot more than that is 7 feet. Our answer checks out.
The width of the door is 3 feet.
Hope this helps!
This doesn't make sense, as a triangle much equal 180, so it cannot have two angles bigger than 90, because this would mean it cannot be acute. A right triangle has one angle that is 90, obtuse as one that is bigger than 90 and two that are less, and an acute has three angles less than 90. Maybe there's a typo here?
Answer:
c
Step-by-step explanation:
Answer:
I'm going with B, but i did some research.
Step-by-step explanation:
Answer:
3x + 6
Step-by-step explanation:
it literally says bc = 3x + 6
