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MariettaO [177]
3 years ago
14

6) A jet travels 480 miles in 2 hours. At this rate, how far could the jet fly in

Mathematics
2 answers:
Sveta_85 [38]3 years ago
7 0
I need help on this too
Arte-miy333 [17]3 years ago
4 0

Answer:

1,920 is how far the jet travels in 8 hours, the rate of the jet is 240 meaning it would travel 240 miles in 1 hour,

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What is $220 marked up 60%​
NNADVOKAT [17]

Answer:

Answer would be $366.70

Step-by-step explanation:

220/60%=366.70

Hope it helps

4 0
3 years ago
Read 2 more answers
The population of New York City is 23,945. Eastdale has a population of 12,774 What is the total population of the two communiti
serious [3.7K]
No.d
37,619

I hope that this helps you and please mark me as the brainliest.
3 0
2 years ago
Can someone answer this correctly pls
AleksandrR [38]

Answer:

i = 45% and ii = 47% (Rounded)

Step-by-step explanation:

Simply divide 27 by 60 to get i:

27/60=.45

Convert to a percent chance.

.45=45%

Then divide 395 by 840 to get ii:

395/840=.47

Convert to a percent chance.

.47=47%

8 0
2 years ago
Researchers studying the acquisition of pronunciation often compare measurements made on the recorded speech of adults and child
dolphi86 [110]

Answer:

(A) The additional information that is needed to confirm about the conditions for this test have been met is ‘Population is approximately normal.

(B) The test statistic = 1.9965

(C1) P-value = 0.0556

(C2) There is no significant difference between mean VOT for children and adults.

D1) It is possible to make type II error.

(D2) There should be a difference in the VOT of adults and children.

Step-by-step explanation:

Let na be the number of adults = 20

xa mean VOT for adults = 88.17

sa standard deviatiation of VOT for adults = 24.74

Let nc be the number of children = 10

xc mean VOT for children =60.67

sc standard deviatiation of VOT for children = 39.89

(A) From the information the population variances are unknown and the two sample are assumed to be independent and the sample the sample size are smaller that is (n<30).

This indicates that the additional information that is required for the conditions of the test to be satisfied is 'distribution of the population'. the addition assumption to be made is, that the population distribution is normal.

(b) Calculating the test statistics using the formula;

t = (xa -xc)/SE - d

where SE = standard deviation , d= hypothesized difference = 0

But SE = √sa²/na +sc²/nc

           = √24.74 ²/20 + 39.89²/10

           = √189.72559

           = 13.774

Substituting into test statistics equation, we have

t = (xa -xc)/SE - d

  = (88.17 - 60.67/13.774

  = 1.9965

Therefore the test statistic is 1.9965

(c) Calculating the p-value, we have;

Degree of freedom = na + nc -2

                                 = 10+ 20 -2

                                 = 28

The p-value for t=1.9965 at 28 degrees of freedom and 0.05 level of significance is 0.0556.

The p-value 0.0556 is greater than given level of significance 0.05 hence we fail to reject the null hypothesis and conclude that there is no significant difference between mean VOT for children and adults.

(D1) From the information in part (C) the null hypothesis is not rejected.

Since the null hypothesis is not rejected, there might be a chance that not rejecting null hypothesis would be wrong. In this type of situation the error that can occur would be type II error.

(D2) The type of error describe in the context of this study is obtained by the concept of the type II error which tells that the null hypothesis is not rejected when it is actually false.

7 0
3 years ago
Graph the line for y+1=−3/5(x−4) on the coordinate plane
Andrej [43]
Solve for y:
y + 1 = -3/5x + 2.4  (multiply 4 by 3/5 no negatives because negative times a negative is a positive)
y = -3/5x + 1.4
Now graph the y-intercept of 1.4. 
Then plot points using slope. 
Hope this helps and let me know if you have more questions!
7 0
3 years ago
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