2 years ago

Im stuck :( ' Helpppppppppppppppppppppppppppppppppppppppppppp

Mathematics

1 answer:

Kobotan [32]2 years ago

8 0

A. 2/10 is the correct answer

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artcher [175]

300=(1/6*7/8)x
300=7/48x
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So the answer is B

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4 0

3 years ago

Read 2 more answers

Write three equations whose solution is x=3.5

My name is Ann [436]

Answer:

1. 2x + 23 = 30

2. 3x + 19.5 = 30

3. (10x - 20)/ 5 = 3

Explanation:

Work backward:

1. 2x + 23 = 30

Start:

x = 3.5

Multiply the equation by 2:

2x = 2 (3.5)
2x = 7

Subtract 30 from both sides

2x - 30 = 7 - 30
2x - 30 = -23

Add 23 and 30 to both sides:

2x + 23 = 30

2. 3x + 19.5 = 30

Start:

x = 3.5

Add 6.5 to both sides:

x + 6.5 = 10

Multiply by 3:

3(x + 6.5) = 30

Distributive property:

3x + 19.5 = 30

3. (10x - 20)/ 5 = 3

Start:

x=3.5

Multiply by 10:

10x = 35

Subtract 20:

10x - 20 = 15

Divide by 5:

(10x - 20)/ 5 = 15/5

(10x - 20) / 5 = 3

3 0

3 years ago

CAN SOMEONE PLEASE HELP ME WITH MY HOMEWORK ILL DO ANYTHING FOR HELP JUST PLEASE HELP ME WITH MY HOMEWORK AND PLEASE EXPLAIN HOW

icang [17]

Answer:

the simplest way to finish your hw is to ask the Q of your hw here instead of asking us to help with your hw

5 0

2 years ago

Read 2 more answers

3.) You deposited $5,000 in an account that pays 4% annual interest. Find the

Maurinko [17]

The balance after one year is $5200

Step-by-step explanation:

The formula to apply here is

$A=P(1+\frac{r}{n} )^{nt}$

where

A=Amount of money at the end of the period=?

P=the amount of money invested= $5000

r=rate of interest=4%=0.04

n=number of compounding per year=1

t=time in years=1

Applying the formula

$A=P(1+\frac{r}{n} )^{nt} \\\\\\A=5000(1+\frac{0.04}{1} )^{1} \\\\\\A=5000(1.04)\\\\A=5200$

A=$5200

Learn More

Compound Interest: brainly.com/question/12148233

Keywords : interest, compounded annually

#learnwithbrainly

6 0

3 years ago

What are the solutions of the quadratic equation x^2=9x+6

Alexandra [31]

See Quadratic Formula and Determinant's/Delta's formula

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2 years ago