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3 years ago

How is the Pythagorean theorem related to the distance formula? Explain.

Mathematics

2 answers:

spayn [35]3 years ago

6 0

Answer:

The distance formula is a formalisation of the Pythagorean Theorem using (x,y) . They are the same thing (but the distance formula is for working out the distance between two points and Pythagoras theorem is for working out the missing length in a right-angled triangle) in two different contexts.

Step-by-step explanation:

Levart [38]3 years ago

3 0

Answer:

Both formulas can be used to find the distance between two points on the coordinate plane. The vertical leg of the right triangle represents the difference in the y values of the two points. The horizontal leg of the right triangle represents the difference in the x values of the two points. The hypotenuse of the right triangle represents the distance between the two points.

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Eureka Math : 5 ÷ 1/3= ____. There are ___ thirds in 1 whole. There are ___ thirds in 5 wholes. If 5 is 1/3, what is the whole?

oksian1 [2.3K]

Let me edit your question to simplify it.

Eureka Math :

A)5 ÷ 1/3= ____.

B) There are ___ thirds in 1 whole.

C) There are ___ thirds in 5 wholes.

D) If 5 of 1/3, what is the whole? ___

E) 3 ÷1/5= ____ .

F) There are ___ fifths in 1 whole.

G) There are ___ fifths in 3 wholes.

H) If 3 of 1/5, what is the whole?___

Answer:

A) 15

B) three thirds

C) 15 wholes

D) whole is 2

E) 15

F) five fifths

G) 15 fifths

H) whole is 1

Step-by-step explanation:

$5$ ÷ $\frac{1}{3} =5*\frac{3}{1}$

$5$ ÷ $\frac{1}{3}=15$

Third:

third means $\frac{1}{3}$

To make 1 whole from thirds, we need three thirds i.e. $\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=\frac{3}{3}=1\ Whole$

In 1 whole there are three thirds, so in 5 wholes there are $5*3=15$ wholes.

In $5\ of\ \frac{1}{3}=5*\frac{1}{3} =\frac{5}{3}$

$\frac{5}{3}=1.6$

The whole of $1.6$ or $\frac{5}{3}$ is 2 (rounding 1.6 to 2)

$3$ ÷ $\frac{1}{5}=3*5=15$

Fifth: means $\frac{1}{5}$

To make 1 whole of fifths we need five fifths i.e. $\frac{1}{5} +\frac{1}{5} +\frac{1}{5} +\frac{1}{5} +\frac{1}{5}=\frac{1+1+1+1+1}{5}=\frac{5}{5}=1$