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Oduvanchick [21]
4 years ago
15

The product of a number and five is eight

Mathematics
1 answer:
artcher [175]4 years ago
3 0

Answer:

Assuming x is the number, then x=1.6

Step-by-step explanation:

If the product of a number and 5 is 8, the equation becomes:

5x=8 (assuming x is the unknown number).

We can isolate the variable x by dividing both sides by 5.

5x\div5 = 8\div5\\x = 1.6

Hope this helped!

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Step-by-step explanation:

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Solve x divided by four equals eight . (1 point)<br><br><br> 4<br> −4<br> 32<br> −32
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Read 2 more answers
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
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aniked [119]

Answer:

5/2

Step-by-step explanation:

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7 0
3 years ago
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