Yes it's the process of entering data into a database.
<h2>Hello!</h2>
The answer is:
- CD
- DVD
- UDO
<h2>Why?</h2>
Optical disks are circular disks used as storage for binary data usually made of polycarbonate. The data is stored in the disc using a laser machine and accessed using a laser diode illuminating the data path in an optical disc drive.
CD: Compact Discs are the most basic optical disk used today, with only a capacity that goes from 0.7 GB (700 MB) to 0.84 GB (840 MB).
DVD: Digital Versatile Discs increase the storage up to 6 times compared with a CD, the capacity of DVDs optical disks goes from 4.7 GB (4700 MB) to about 17 GB(17000 MB).
UDO: Ultra Density Optical have high capacity storage that goes from 30 GB (30000 MB) to about 60 GB (6000 MB).
Have a nice day!
Implement the simulation of a biased 6-sided die which takes the values 1,2,3,4,5,6 with probabilities 1/8,1/12,1/8,1/12,1/12,1/
hjlf
Answer:
see explaination
Explanation:
import numpy as np
import matplotlib.pyplot as plt
a = [1, 2, 3, 4, 5, 6]
prob = [1.0/8.0, 1.0/12.0, 1.0/8.0, 1.0/12.0, 1.0/12.0, 1.0/2.0]
smls = 1000000
rolls = list(np.random.choice(a, smls, p=prob))
counts = [rolls.count(i) for i in a]
prob_exper = [float(counts[i])/1000000.0 for i in range(6)]
print("\nProbabilities from experiment : \n\n", prob_exper, end = "\n\n")
plt.hist(rolls)
plt.title("Histogram with counts")
plt.show()
check attachment output and histogram
Mechanical mouse has a ball that turns rollers inside. If friction is lost between the ball and the mousing surface, or between the ball and the rollers, the mouse fails to work. In order to assure good contact with the mousing surface, the ball must be fairly heavy. When you change directions with the mouse, you must make the ball change rolling directions--an action that inertia likes to prevent.
An optical mouse makes use of an LED and some optics to detect surface texture and the changes in it as the mouse is moved. There are no moving parts
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
