2x^2 + 17x -21 cannot be factored nicely, if it was +21 you could, but the zeros for this have to gotten using the quadratic equation
-b +/- (b^2-4ac)^1/2
2a
so
-17 +/- (17^2-4(2)(-21))^1/2
2(2)
-17 +/- (457)^1/2
4
so the zeros are roughly 1.094 and -9.594
Answer:
A = 15t +15
Step-by-step explanation:
The amounts have a common difference of $15, so that is apparently the amount Jasmine is saving each week. Week 1, however, is $15 more than $15×1. The function ...
A = 15t +15 . . . . dollars
seems to fit the data.
The answer would be 0.4
You can first reduce this fraction:
40/100
=25
=
2
—
5
=2÷5
=
2
÷
5
=0.4
=
0.4
Answer:
(a)
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b)
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by
Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4
Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Refer to attachment for your answer