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3 years ago

Find the slope and the y-intercept of the graph of y=11+1.5x.

Mathematics

2 answers:

Anni [7]3 years ago

6 0

Honestly man i don’t know Im in 6th grade bro

VashaNatasha [74]3 years ago

5 0

Answer:

Step-by-step explanation:

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A. 8pi B. pi C. 2pi D. 4pi

mestny [16]

Answer: Option C

$AC = 2\pi$

Step-by-step explanation:

The arc length is calculated as

$L = \theta * R$

Then

$AC = \theta * R$

We know that

$BC = 24\ ft$

If BC is the diameter of the circumference then the radius R is:

$R = \frac{BC}{2}$

$R = \frac{24}{2}$

$R = 12\ ft$

Now we convert the anglo from degrees to radians $\theta= 30\° * \frac{\pi}{180\°}\\\\\theta=\frac{1}{6}\pi$

Finally

$AC = \frac{1}{6}\pi * 12$

$AC = 2\pi$

7 0

3 years ago

Read 2 more answers

Please help i will give a lot of points if corrected

Sloan [31]

Answer:

1. <ABD.3 2.<CBD.M3

Step-by-step explanation:

i hope it helps

stay safe

correct me if im wrong

#carryonlearning

3 0

2 years ago

Read 2 more answers

Jorge asked each of the 24 students in his class if they play a musical instrument. He also asked each student if they play a sp

Pepsi [2]

Answer:

play a musical don't play a musical Total

instrument instrument

play an sport 6 14-6 = 8 14

don't play an sport 10-3 = 7 3 24 -14 = 10

Total 6+7 = 13 8+3 = 11 24

Step-by-step explanation:

Data is In italic.

5 0

3 years ago

I need help with this math work

Marizza181 [45]

What are the directions for this?

7 0

3 years ago

In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?

Sophie [7]

Answer: 1440

Step-by-step explanation:

To arrange 3 boys and 4 girls such that no two boys are together.

Since boys should be arranged between the girls.

So first arrange the girls.

Assume that the girls are placed, then there will be 5 spaces left for 3 boys.

The number of combinations to fill these places = $^5C_3=\dfrac{5!}{3!2!}=\dfrac{5\times4}{2}=10$

Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways

4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways

Then, the total number of arrangements = 10 x 6 x 24 = 1440

Hence, the required number of arrangements = 1440

5 0

3 years ago