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2 years ago

8

Which does not show a direct variation between x and y?PLZZZ HELP ASAP?

2 answers:

svetoff [14.1K]2 years ago

6 0

A direct variation equation takes the form y=kx, where k is a constant.

Choice A displays a direct variation since it takes the form y=kx, where k=5.

Choice B does NOT display direct variation because x is in the denominator. This relationship between x and y in choice B is called inverse variation.

Choice C displays direct variation since it takes the form y=kx, where k=0.7

Choice D displays direct variation since it takes the form y=kx, where k=1/9.

In conclusion, your answer is CHOICE B. Have an awesome day! :)

Anon25 [30]2 years ago

3 0

Y = 6/x does not show a direct variabtion

Answer
B. y = 6/x

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Any help would be appreciated! :)

ikadub [295]

Answer:

-7, then -13, then -19

Step-by-step explanation:

Plug in x values to get y.

y = -2(0) - 7

y = 0 - 7

y = -7

y = -2(3) - 7

y = -6 - 7

y = -13

y = -2(6) - 7

y = -12 - 7

y = -19

Hope this helps. :0)

7 0

1 year ago

Read 2 more answers

What is the fraction that is less then 5/8

Rashid [163]

Answer:

4/6

Step-by-step explanation:

8 0

2 years ago

Work out the area of this shape

amm1812

Answer:

1000

Step-by-step explanation:

3 0

2 years ago

Help please explain

MatroZZZ [7]

Given:

$\sin^{-1}\left(\dfrac{5}{8}\right)=A$

To find:

The correct equivalent equation.

Solution:

We have,

$\sin^{-1}\left(\dfrac{5}{8}\right)=A$

Taking sin on both sides, we get

$\sin \sin^{-1}\left(\dfrac{5}{8}\right)=\sin A$

$\dfrac{5}{8}=\sin A$ $[\because \sin (\sin^{-1}\theta )=\theta]$

Interchanging the sides, we get

$\sin A=\dfrac{5}{8}$

Therefore, the correct option is 4.

8 0

2 years ago

Add the following polynomials, then place the answer in the proper location on the grid.

aivan3 [116]

Answer:

$x^3 - 6x + 2$

Step-by-step explanation:

The given polynomials can be added together by adding like terms together as shown below:

=> Add together, the coefficient of all terms that have the power of 3.

$(2x^3) + (x^3) + (-3x^3)$

$2x^3 + x^3 - 3x^3$

$3x^3 - 3x^3$

$x^3$

=> $(-4x^2) + (6x^2) + (2x^2)$

$-4x^2 + 8x^2$

$4x^2$

=> $(6x) + (-8x) + (-4x)$

$6x - 8x - 4x$

$-6x$

=> $(-3) + (12) +(-7)$

$-3 + 12 - 7$

$2$

The answer = $x^3 - 6x + 2$

5 0

2 years ago