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Arada [10]
3 years ago
15

Need help ! Can someone draw it plz

Mathematics
1 answer:
Luba_88 [7]3 years ago
5 0

Answer:

Step-by-step explanation:

should look something like this

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Is -2x2y3z an expression or equation?
DochEvi [55]

Answer:

expression

Step-by-step explanation:

expressions DON'T have equal signs but equations do.

7 0
3 years ago
A square has side length (x+5) units. What is it’s area
daser333 [38]

The area of square is x^{2}+10 x+25 square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

\text {Area of square }=\mathrm{a}^{2}

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

\text {Area of square }=(x+5)^{2}

{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}

\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}

Thus the area of square is x^{2}+10 x+25 square units

7 0
3 years ago
On Monday, a bakery sold 67 dozen cookies. How many total cookies did the bakery sell?​
gulaghasi [49]

Answer:

804

Step-by-step explanation:

dozen means 12

67 times 12 is 804

8 0
2 years ago
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You spend $40 on 5 Pounds of concreate what is the<br> 1 unit rate in dollars
Umnica [9.8K]

Answer:

$8

Step-by-step explanation:

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2 years ago
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SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as
vovangra [49]

Answer:

a) P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)

P(Z>1.25)=1-P(Z

b) P(400

P(-1

P(-1

c) z=-0.842

And if we solve for a we got

a=500 -0.842*100=415.8

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

X \sim N(500,100)  

Where \mu=500 and \sigma=100

We are interested on this probability

P(X>625)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>1.25)=1-P(Z

Part b

We are interested on this probability

P(400

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(400

And we can find this probability with this difference:

P(-1

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1

Part c

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.8   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=500 -0.842*100=415.8

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.  

8 0
3 years ago
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