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3 years ago

Need help ! Can someone draw it plz

Mathematics

1 answer:

Luba_88 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

should look something like this

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Witch expression is equivalent to (cd)5?

Aleks04 [339]

Answer:

Step-by-step explanation:

the expression is equivalent to (cd)5 : c^5×d^5

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4 years ago

Which is the quotient of 6 divided by 1/4

muminat

24. Hope this helps:)

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3 years ago

Read 2 more answers

you want to put $8000 in a simple interest account. it has 2% annual interest rate. how long less you have invest that money to

Lisa [10]

Answer:

3 years

Step-by-step explanation:

160 per year, 160*2=320, 160*3=480

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3 years ago

In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x

Alexus [3.1K]

Answer:

Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

Step-by-step explanation:

Given Differential Equation,

$y"-2y'+y=xe^x$ ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

$\implies\:y(x)=y_c(x)+y_p(x)$

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

$y_c(x)=C_1e^x+c_2xe^x$

Now for particular solution,

let $y_p(x)=Ax^3e^x$

$y'=Ax^3e^x+3Ax^2e^x$

$y"=Ax^3e^x+6Ax^2e^x+6Axe^x$

Now putting these values in (1), we get

$Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x$

$Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x$

$6Axe^x=xe^x$

$6A=1$

$A=\frac{1}{6}$

$\implies\:y_p(x)=\frac{x^3e^x}{6}$

Therefore, Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

8 0

4 years ago

Solve the equation 4^2x = 9

Bas_tet [7]

Answer:

x=9/16

Step-by-step explanation:

Divide each term by 4 ^2 and simplify.

8 0

4 years ago